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Triss [41]
2 years ago
6

Help :((((( this is hard

Mathematics
1 answer:
iren2701 [21]2 years ago
3 0

Step-by-step explanation:

y - y1 = m (x - x1)

(y - y1)/m = x - x1

x - x1 = (y - y1)/m

x = (y - y1)/m + x1

therefore, answer is option C

Topic: Change of subject / coordinate geometry

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

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Peter wants to test an assumption on the number of trees that tested positive for a particular infestation. He decides to focus
LUCKY_DIMON [66]

Answer:

H0 : P ≤ 0.12

H1 : P > 0.12

Step-by-step explanation:

12% = 12/ 100 = 0.12

Given the population proportion, P = 0.12

The claim is the alternative hypothesis, H1 ; which is to test if more than 12% of trees have been infested.

Hence, the alternative hypothesis will be ;

H1 : P > 0.12

The null hypothesis which is the initial truth is always the opposite of the alternative hypothesis, Therefore, we write our null as ;

The null hypothesis ; H0 : P ≤ 0.12

Therefore, we have :

H0 : P ≤ 0.12

H1 : P > 0.12

4 0
2 years ago
Can a triangle have sides of length 4,7,11?
Lesechka [4]

Answer:

No because 16+49 does not equal 121.

Step-by-step explanation:

first make 11 the hypotenuse and 4 and 7 side b and A

Use the pythagorean theorem: A^2+B^2=C^2

4^2+7^2=11^2

16+49=121

6 0
3 years ago
12 + x/4 = 9<br> Simplify Plz need ASAP
agasfer [191]

Answer: X = -12

Step-by-step explanation:  1)  12 + x/4 = 9

                                              2)  12 + x/ 2^2 = 9

                                              3)   x/ 2^2  + 12 = 9  

6 0
3 years ago
4294 divided by 68
Nataly_w [17]

Answer:

1. 63.1. 2.22.5 3. 74.3 4. 56.1

8 0
2 years ago
a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.
ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: \mathbf{Length = a -5} and \mathbf{Width = a^2 + 5a + 25}

The area is given as:

\mathbf{Area = a^3 - 125}

Express 125 as 5^3

\mathbf{Area = a^3 - 5^3}

Apply difference of cubes

\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}

\mathbf{Area = (a - 5)(a^2 + 5a + 25)}

The area of a rectangle is:

\mathbf{Area = Length \times Width}

So, by comparison:

\mathbf{Length = a -5}

\mathbf{Width = a^2 + 5a + 25}

Read more about areas at:

brainly.com/question/3518080

6 0
2 years ago
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