Answer:
I'm sorry if this is wrong but try 16 it's probably wrong tho sorry
Note: <em>As you have not added the drawing. So, I assume the total number of two-inch cubes are stacked are FIVE. So, I will explain based on that assumption which anyways will clear your concept.</em>
Answer:
The total surface are will be: ![\boxed{120\:\:sq.in}](https://tex.z-dn.net/?f=%5Cboxed%7B120%5C%3A%5C%3Asq.in%7D)
Step-by-step explanation:
As we know that
- A cube contains
faces of equal area.
So, the total surface area of the cube is equal to
multiplied by the area of one of the faces.
As the edge of the cube = 2 inches
So, the area of one of the faces is:
![2\times 2=4\:\:sq.in](https://tex.z-dn.net/?f=2%5Ctimes%202%3D4%5C%3A%5C%3Asq.in)
Thus, the total area of the cube is:
![6\times \:4=24\:\:sq.in](https://tex.z-dn.net/?f=6%5Ctimes%20%5C%3A4%3D24%5C%3A%5C%3Asq.in)
Assuming there are total 5 cubes which are stacked, so the total surface are will:
![24\times 5=120\:\:sq.in](https://tex.z-dn.net/?f=24%5Ctimes%205%3D120%5C%3A%5C%3Asq.in)
Therefore, the total surface are will be:
16.5+4.73= 21.23 it’s basically regular adding just with decimal
Answer:
Try the suggested solution, shown on the picture attached
Step-by-step explanation:
Note, 'm(MNO)' means m(∠MNO), and for issues 2, 4 ,5 - the described angles are angles inside the declared triangle.