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iogann1982 [59]
3 years ago
8

2). The scale factor of two regular octagons is 52. Find the ratio of their

Mathematics
1 answer:
vampirchik [111]3 years ago
8 0

Answer:

Step-by-step explanationBy definition we have that the area of a regular octagon is:

A = 4.83L ^ 2

Where, L is the length of the octagon side.

the similarity ratio = the area ratio.

We have then:

similarity ratio = (50) / (18) = 25/9.

the ratio of the perimeters

A1 = 4.83L1 ^ 2

L1 ^ 2 = A1 / 4.83

L2 ^ 2 = A2 / 4.83

L1 ^ 2 / L2 ^ 2 = A1 / A2 = 25/9

L1 / L2 = 5/3

The perimeter is:

P1 = 8L1

P2 = 8L2

P1 / P2 = 8L1 / 8L2 = L1 / L2 = 5/3

answer:

similarity ratio:

25: 9

the ratio of the perimeters:

5: 3

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Step-by-step explanation:

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co-ordinate of B= (4,2) = (x2,y2)

co-ordinate of C= (3,-3) = (x3,y3)

co-ordinate of D= (-7,-1) = (x4,y4)

In rectangle ABCD

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Now, using distance formula

AB = √(x2-x1)² + (y2-y1)²

     =√(4-(-6))²+ (2-4)²

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      =√100+4

      =√104

      =2√26 units

so,AB = CD = 2√26 units

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     BC = √(x3-x2)² + (y3-y2)²

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    =2.3√26

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