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monitta
3 years ago
12

Which theorem proves the triangles congruent? A- ASA B- SSA C- HL D- SAS

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0

Answer:

HL

Step-by-step explanation:

The HL Therom only proves right triangles are congruent and since both triangles are right triangles, HL can work here.

LekaFEV [45]3 years ago
7 0

Answer:

um

Step-by-step explanation:

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Please help ASAP! The terminal side of an angle θ in standard position passes through the point (2,-5). calculate the values of
Troyanec [42]

Answer:

sin(x)=\frac{opp}{hyp}=\frac{5}{\sqrt{21}}=\frac{5\sqrt{21}}{21}\\cos(x)=\frac{adj}{hyp}=\frac{2}{\sqrt{21}}=\frac{2\sqrt{21}}{21}\\tan(x)=\frac{opp}{adj}=\frac{5}{2}\\csc(x)=\frac{hyp}{opp}=\frac{\sqrt{21}}{5}\\sec(x)=\frac{hyp}{adj}=\frac{\sqrt{21}}{2}\\cot(x)=\frac{adj}{opp}=\frac{2}{5}

Step-by-step explanation:

Start by drawing out the triangle on the graph:

(See picture)

(By the drawing you can judge me that I am a really bad artist)

Theta and the side lengths are labeled, the hypotenuse has a length of √21 by Pythagora's theorem. Now, time to put everything to the trigonometric functions:

sin(x)=\frac{opp}{hyp}=\frac{5}{\sqrt{21}}=\frac{5\sqrt{21}}{21}\\cos(x)=\frac{adj}{hyp}=\frac{2}{\sqrt{21}}=\frac{2\sqrt{21}}{21}\\tan(x)=\frac{opp}{adj}=\frac{5}{2}\\csc(x)=\frac{hyp}{opp}=\frac{\sqrt{21}}{5}\\sec(x)=\frac{hyp}{adj}=\frac{\sqrt{21}}{2}\\cot(x)=\frac{adj}{opp}=\frac{2}{5}

(Suppose that x is theta as I can't type it)

By some basic understanding that's all that I can do.

3 0
2 years ago
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