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Rina8888 [55]
2 years ago
6

What are the coordinates of the midpoint of AB? (-2 ,1/2) (-3/2 ,-1) (-1,3/2) (-1/2, -2)

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
3 0

Answer:

To calculate it:

Add both "x" coordinates, divide by 2.

Add both "y" coordinates, divide by 2.

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Trapezoid and paralellogram are both quadrilaterals

the heiarchy is
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so you can see that they are both quadrilaterals (quad=4, lateral=sides, quadrilateral=4 sided figure)
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What is a probability ?
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Step-by-step explanation:

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\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}

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