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sp2606 [1]
3 years ago
15

Hasib earns 30 cents for every carrot he sells.

Mathematics
2 answers:
Anna [14]3 years ago
5 0

Answer:

He must sell 1390 carrots

Step-by-step explanation:

30x + 300x/30 = 55500

40x = 55500

x = 1387.5

1387.5

multiply 30 by .3 to get $9 for 30 carrots

Then add $3 to this amount to get $12 dollars.

Divide 555 by 12 to get 46 R3.

Multiply 46 by 30 because its 46 bundles of 30 carrots

Then divide the 3 dollars by .3 for each carrot to get 10 carrots

1380+10 = 1390

olganol [36]3 years ago
4 0

Answer:

185

Step-by-step explanation:

if you divide 555 to 3, you get 185

hope that helps :))

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Least common denominator of 6/7 and 5/14
Darya [45]

Answer:

14

Step-by-step explanation:

You can‘t simplify 5/14 because 5 is a prime number. So, now you have to convert the 6/7 to 12/14 to match it up to 5/14. They now have a common denominator of 14.

Hope this helps! :)

5 0
3 years ago
8/66<br> A.)7 <br> B.)8<br> C.)7 remainder of 2 <br> D.)8 remainder of 2
trapecia [35]

Don't you mean 66 divided by eight?

That would equal 8.25, or 8 remainder 2.

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5 0
3 years ago
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A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of
notsponge [240]

Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

M = z\frac{\sigma}{\sqrt{n}}

0.0001 = 2.327\frac{0.0003}{\sqrt{n}}

0.0001\sqrt{n} = 2.327*0.0003

\sqrt{n} = \frac{2.327*0.0003}{0.0001}

(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2

n = 48.73

Rounding up

49 measurements are needed.

7 0
2 years ago
Graph the equation.<br> y = 1/3 (x + 3)(x – 3)
kolbaska11 [484]

Answer:

Step-by-step explanation:

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6 0
3 years ago
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How do I Simplify (5x-2)4 using the distributive property?
BartSMP [9]

Answer:

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Step-by-step explanation:

using the distributive property to simplify (5x-2)4, you would multiply the outside term (4) by each inside term (5x-2).

for example:

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3 years ago
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