When only angles are specified, the sides can be any length, so the triangle is not unique. In any event, the sum of angles must be 180°, so three angles measuring 50° cannot be closed to form a triangle.
Three sides measuring 4, 8, and 14 ft cannot be closed, either, as the long dimension exceeds the sum of the other two. The ends can't meet.
The appropriate choice is the 3rd one ...
... three sides measuring 5 in, 12 in, and 14 in.
Answer:
The distance is (-4,3)
Step-by-step explanation:
count between the numbers :)
Answer:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
Step-by-step explanation:
Solve for b:
b - (3 + 2/5) = 8 + 1/5
Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:
b - (5×3)/5 + 2/5 = 8 + 1/5
5×3 = 15:
b - (15/5 + 2/5) = 8 + 1/5
15/5 + 2/5 = (15 + 2)/5:
b - (15 + 2)/5 = 8 + 1/5
15 + 2 = 17:
b - 17/5 = 8 + 1/5
Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:
(5 b)/5 - 17/5 = 8 + 1/5
(5 b)/5 - 17/5 = (5 b - 17)/5:
(5 b - 17)/5 = 8 + 1/5
Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:
(5 b - 17)/5 = (5×8)/5 + 1/5
5×8 = 40:
(5 b - 17)/5 = 40/5 + 1/5
40/5 + 1/5 = (40 + 1)/5:
(5 b - 17)/5 = (40 + 1)/5
40 + 1 = 41:
(5 b - 17)/5 = 41/5
Multiply both sides of (5 b - 17)/5 = 41/5 by 5:
(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 41
Add 17 to both sides:
5 b + (17 - 17) = 17 + 41
17 - 17 = 0:
5 b = 41 + 17
41 + 17 = 58:
5 b = 58
Divide both sides of 5 b = 58 by 5:
(5 b)/5 = 58/5
5/5 = 1:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
