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Lisa [10]
3 years ago
13

. Theo is comparing shark lengths. He learned that a horn shark is 2 3/4 feet long. A blue shark is 4 times as long. Use the bar

model. How long is a blue shark?
A 8 3/4 feet

B 11 feet

C 12 1/4 feet

D 13 feet
Mathematics
1 answer:
umka21 [38]3 years ago
6 0

Answer:

11

Step-by-step explanation:

2 3/4 times 4 equals 11

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Niko spent $23.25 a raffle ticket that cost $.75 each which of the following is the number of raffle tickets nickel bought
miskamm [114]

Answer:

31 raffle tickets

Step-by-step explanation:

23.25 divided by 0.75 = 31

8 0
3 years ago
Read 2 more answers
Lucy is laying tile around the edge of a counter that is 6.4 feet by 2.7 feet. If each tile is 6 inches long, and Lucy buys 30 t
polet [3.4K]

Answer:

Tiles won't be enough

Step-by-step explanation:

The perimeter of the area :

2(length + Width)

Given dimension = 6.4 by 2.7 feets

Perimeter = 2(6.4 + 2.7) = 18.2 feets

1 feet = 12 inches

Perimeter = 18.2 * 12 = 218.4 inches

1 tile = 6 inches

30 tiles = 6* 30 = 180 inches

Since the perimeter of the area is greater Than the 180, then we can conclude that the tiles won't be enough

5 0
3 years ago
Write an equation in point-slope form for the line that passes through the point with the given slope. (–2, 11), m=43
frosja888 [35]

Answer:

y-11=43(x+2)

Step-by-step explanation:

y-y1=m(x-x1)

y-11=43(x-(-2))

y-11=43(x+2)

4 0
3 years ago
Which of the following choices is the variance of the sample shown here? 35 37 42 57 61 70
viktelen [127]

Answer:

205.5. should be it!


3 0
4 years ago
Read 2 more answers
el perimetro de un terreno rectangular es de 170m y su area es de 170^2hallar la medida de sus lados con ecuacion cuadratica
Blizzard [7]

Answer:

Acá tenemos un sistema de ecuaciones.

El perímetro de un rectángulo es:

2*A + 2*L = 170m

donde A es el ancho y L es el largo.

Y el área del rectángulo es:

A*L = 170m^2.

Entonces, el primer paso es aislar una de las variables en una de las ecuaciones, yo voy a aislar A en la segunda:

A = 170m^2/L.

Ahora reemplazo eso en la primera ecuación y la resuelvo para L.

2*( 170m^2/L.) + 2*L = 170m.

340m^2 + 2*L^2 = 170m*L

ahora tenemos una ecuación cuadrática:

2*L^2 - 170m*L + 340m^2 = 0.

Las soluciones se pueden obtener usando la formula de Bhaskara:

L = \frac{+170 +- \sqrt{170^2 -4*340*2}  }{2*2} = \frac{170 +-161.8}{4}

Entonces las soluciones son:

L = (170 + 161.8)/4 = 82.95m

L = (170 - 161.8)/4 = 4.1m

Entonces, si tomamos L = 82.95m, tenemos A = 4.1 m

y el área es:

A*L = 4.1m*82.95m = 170m^2

3 0
3 years ago
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