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allochka39001 [22]
3 years ago
6

Mr. Gordon has 13 girls and 14 boys in his fourth period algebra class. One person is chosen at random.

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0

Answer:

E

Step-by-step explanation:

It's E because you have to add 13 and 14 and as you can see there's 14 boys so it's E.

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Find vertex of f(x)=(x+3)(x-5)
astra-53 [7]

The x coordinate of the vertex will be the average of the two zeros, here -3 and 5, so x=(-3+5)/2 = 1, f(1)=(1+3)(1-5) = -16.

Answer: (1, -16)

Let's do it some other ways.  How about completing the square to turn f in to vertex form?

f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16

and now we can read off (1, -16) as the vertex.

The other method is the vertex is x= - b/2a =  - (-2)/2(1) = 1.

Three methods, same answer. Good.

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2 years ago
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The Marriott Hotel charges $150 per night for a family
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Answer:

For two night in the hotel, you would pay $333 (including tax)

Step-by-step explanation:

Without tax, the price for 2 nights would be $150 times 2. So the price without tax would be....

$150 x 2 = $300

But then we have to be aware of 11% tax so we would multiply the price for two nights by 1.11 and get...

$300 x 1.11 = $333

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3 years ago
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(x-5°<br> 22what is the answer
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Answer:

x-5

Step-by-step explanation:

4 0
3 years ago
When a number x is multiplied by 9, the result is 63. What is the value of x?
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What is the opposite of multiply? division. 63÷9=7
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4 0
2 years ago
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What are the solutions of the equation x4+3x2+2=0? use u substitution to solve
sweet [91]

Answer: x = ± i , x = ±√2i are solution .

Step-by-step explanation:

Given : x^{4} +3x^{2} +2=0, use u substitution to solve.

To find : what are the solutions of the equation .

Solution : We have given that x^{4} +3x^{2} +2=0.

Let consider x^{2} = u .

Substitute u =  x^{2} in given equation .

u^{2} + 3u +2=0.

On factoring

u^{2} + 2u+1u +2=0.

Taking common

u( u+2) +1 (u+2) = 0.

On grouping

(u+1) (u+2) =0

Now, u+1 = 0 ⇒ u = -1.

         u+2 = 0 ⇒ u = -2.

In term of x, plugging x^{2} = u.

x^{2} = -1   ;  x^{2} = -2.

taking square root both side

x = ± i

x = ±√2i.

Therefore, x = ± i , x = ±√2i are solution .

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