Answer:
#include <iostream>
using namespace std;
int main() {
int k;
double d;
string s;
cin >> k >> d >> s;
cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s; }
Explanation:
k is int type variable that stores integer values.
d is double type variable that stores real number.
s is string type variable that stores word.
cin statement is used to take input from user. cin takes an integer, a real number and a word from user. The user first enters an integer value, then a real number and then a small word as input.
cout statement is used to display the output on the screen. cout displays the value of k, d and s which entered by user.
First the values of k, d and s are displayed in reverse order. This means the word is displayed first, then the real number and then the integer separated again by EXACTLY one space from each other. " " used to represent a single space.
Then next line \n is used to produce a new line.
So in the next line values of k, d and s are displayed in original order (the integer , the real, and the word), separated again by EXACTLY one space from each other.
The program along with the output is attached.
The option that is note a new technology-related trends in MIS is co-creation of business value.
<h3>Technology and Management Information System:</h3>
Technology and Management Information System is known to be a term that connote the way a person can know or understand data that is obtained from a lot of units and departments of an organization.
Note that It can be used in the area of integration with other types of technology and as such, The option that is note a new technology-related trends in MIS is co-creation of business value.
Learn more about business value from
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electro-mechanical data storage device
User interface is the answer
Answer and explanation :
the three control problems associated with competing process are
- MUTUAL EXCLUSION : We know that some resources are shareable and some are not shareable. which means only one process can access the resource at a time this type of resources are called critical resources this code can be access at only one process at a time. the other process if required to access should not be allowed
- DEADLOCK: this hold the process without complete for example suppose there are two resources R1 and R2 and two process P1 and P2 and P1 use R1 and P2 use R2 but after some time when P1 needs R2 but R2 is not available as it is used by P2 so the all process will be on hold
- STARVATION : when priorities are given to the process as high priorities and low priorities. And high priorities process always competing then low priorities process have to wait for very long time this is called starvation