Answer:
Comparison.
Explanation:
When we have to find a largest in a list of n elements.First we have to iterate over the list so we can access all the elements of the list in one go.Then to find the largest element in the list we have to initialize a variable outside the loop with the minimum value possible and in the loop compare each element with this value,if the element is greater than the variable assign the element to the variable.Then the loop will find the largest element and it will be the variable.
Answer:
2that is the question??? then many I could help
Answer:
6 2 and 0
Explanation:
This algorithm doesn't work if the list is not ordered ascending.
In this example it is not, and indeed the item "1" is never found.
first cycle: first=0, last=12 so midpoint=6
second cycle: first=0, last=5 so midpoint=2
last cycle: first=0, last=1 so midpoint=0
then last is assigned -1 so the while statement is no longer true.
What's the rest of the question? Like A - B - C - D?
Answer:
Answered below
Explanation:
Scanner n = new Scanner(System.in);
System.out.print("Enter number of guests: ");
int numOfGuests = n.nextline();
double pricePerGuest = 35.0;
double totalAmount = numOfGuests * pricePerGuest;
String event = " ";
if ( numOfGuests >= 50){
event = "Large event";
}else{
event = "small event";
}
System.out.print(numOfGuests);
System.out.println(pricePerGuest);
System.out.println( totalAmount);
System.out.println(event);
