Answer:
It would be -4 + 11 = 7. :D
Step-by-step explanation:
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).
A.
![57=3\cdot19\\ 96=2^5\cdot3](https://tex.z-dn.net/?f=57%3D3%5Ccdot19%5C%5C%0A96%3D2%5E5%5Ccdot3)
Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.
![143=11\cdot13\\ 323=17\cdot19](https://tex.z-dn.net/?f=143%3D11%5Ccdot13%5C%5C%0A323%3D17%5Ccdot19)
Indeed, those two numbers are relatively prime.
Answer:
See below.
Step-by-step explanation:
He does not have enough to loose 2,000,000 at that point, so this whole problem is nonsense.
The answer is 72.375 or just 72.4
579mi/8hrs = 72.375/1hr
7a+16-3a-7= -11
combine like terms
4a+9= -11
add -9 to both sides
4a = - 20
divide by 4
a= -5
hope this helps