1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mylen [45]
3 years ago
13

AM I WRONG JIM? Let me know

Mathematics
2 answers:
Basile [38]3 years ago
7 0
I don’t think you’re wrong good job
Leviafan [203]3 years ago
3 0

Problem 1

Domain:   [-3, 5)

Range:    (-4, 3]

The domain is the set of allowed x inputs, while the range is the set of allowed y outputs. For problems like this, we just list the smallest and largest values possible. In this question, the left most point happens when x = -3 and the right most point is when x = 5, but we don't include this value due to the open hole. So that's why we have a curved parenthesis as part of the domain here. The range is a similar story, but we look at the y values instead.

==========================================

Problem 2

Domain:   [-2, 4)

Range:    [-2, 5)

We aren't including any of the endpoints due to the open holes. Be sure not to mix this notation up with ordered pair notation.

===========================================

Problem 3

Domain:  [1, 4]

Range:   [-4, -1]

We include each endpoint because of the filled in circles, so that's why we use square brackets here.

You might be interested in
What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?
BigorU [14]
Y=-3/2x+7/2 is the answer!
7 0
3 years ago
5 2/5 as a mixed number
valentina_108 [34]

Answer:

Mixed numbers have a whole number followed by the fraction (2 1/2). You would say "two and one half." The other format is an improper fraction where the numerator is greater than the denominator (5/2). Mathematicians would say that is five halves.

7 0
3 years ago
Read 2 more answers
The equation 2x^2 + x - 1 = 0 has two solutions. Find an equation of the form ax^2 + bx + c = 0, which solutions....
leonid [27]

Answer:

Step-by-step explanation:

Let the solution to

2x^2 + x -1 =0

x^2+ (1/2)x -(1/2)

are a and b

Hence a + b = -(1/2) ( minus the coefficient of x )

ab = -1/2 (the constant)

A. We want to have an equation where the roots are a +5 and b+5.

Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.

The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.

So the equation is

x^2-(19/2)x + 22 =0

2x^2-19x + 44 =0

B. We want the roots to be 3a and 3b.

Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and

(3a)(3b) = 9(ab) =9(-1/2)=-9/2.

So the equation is

x^2 +(3/2) x -9/2 = 0

2x^2 + 3x -9 =0.

4 0
3 years ago
How do you calculate the common difference?
SCORPION-xisa [38]

Answer:

<h3>                second term minus first term   </h3>

Step-by-step explanation:

Difference is a result of subtracting (not dividing!)

To calculate difference between two terms we have to subtract the previous from the next:

d=a_2-a_1=a_3-a_2=a_4-a_3=...=a_n-a_{n-1}

7 0
3 years ago
The statement "If 1/2x=5, then x=10 is justified by the
Anton [14]
I think it's the Multiplication Property of Equality.

Hope this helps you! :)
6 0
3 years ago
Read 2 more answers
Other questions:
  • Solve the problem 5+x=8
    7·2 answers
  • Erica ran 3 out of 8 Miles. Mariah ran 3 out of 4 miles. Who ran father?
    15·2 answers
  • What the answer to 5
    13·1 answer
  • If each person drink 8 ounces of cranberry juice how much cranberry juice is needed
    11·1 answer
  • Plsss help, will reward brainliest!!! Thank you.<br><br><br><br> Look at picture^^^
    5·1 answer
  • Please help me !
    14·1 answer
  • The angles in a triangle are in the ratio 5 : 3 : 1.
    5·1 answer
  • 5/10 divided by 3/4
    8·2 answers
  • Ahren’s birthday, ​a,​ is less than 6 days away. Which inequality represents Ahran’s birthday? PLz help me
    11·1 answer
  • How to solve this pls? 20 + 46 - 11ab - 6b
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!