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3 years ago

AM I WRONG JIM? Let me know

Mathematics

2 answers:

Basile [38]3 years ago

7 0

I don’t think you’re wrong good job

Leviafan [203]3 years ago

3 0

Problem 1

Domain: [-3, 5)

Range: (-4, 3]

The domain is the set of allowed x inputs, while the range is the set of allowed y outputs. For problems like this, we just list the smallest and largest values possible. In this question, the left most point happens when x = -3 and the right most point is when x = 5, but we don't include this value due to the open hole. So that's why we have a curved parenthesis as part of the domain here. The range is a similar story, but we look at the y values instead.

==========================================

Problem 2

Domain: [-2, 4)

Range: [-2, 5)

We aren't including any of the endpoints due to the open holes. Be sure not to mix this notation up with ordered pair notation.

===========================================

Problem 3

Domain: [1, 4]

Range: [-4, -1]

We include each endpoint because of the filled in circles, so that's why we use square brackets here.

You might be interested in

For the function f(x)=(1/2)⋅6^x , identify the domain, range, y-intercept, and asymptote.

skelet666 [1.2K]

Answer:

Step-by-step explanation:

f(x) = (1/2) *6^x = 2^-1 * 2^x *3^x

y= 2^ (x-1) * 3^x

Domain represents all values that x can have and is all real numbers

Range all values that y can have and is y > 0 ( all real numbers that are positive)

The y-intercept is the point where the graph intersects the y-axis so x=0 there

y = 2^(0-1) *3^0 = 1/2 *1 = 1/2

the asymptote is at y= 0

6 0

3 years ago

Stephen’s lunch bill is currently at $8.33. Stephen orders a fruit salad for take-out, and wants to leave $2.25 as a tip for his

KatRina [158]

Answer:

$4.42

Step-by-step explanation:

by combining $8.33 and $2.25 you get a combined total of $10.58 and if you subtract that from $15 you get $4.42 as the amount of money remaining.

7 0

3 years ago

I need help with my geometry homework .

Nitella [24]

Hi I don't know has to do this

5 0

3 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$

a) Determine the 26th percentile for the number of chocolate chips in a bag. 

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

$Z = \frac{X - \mu}{\sigma}$

$-0.643 = \frac{X - 1262}{118}$

$X - 1262 = -0.643*118$

$X = 1186$

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{X - 1262}{118}$

$X - 1262 = -1.96*118$

$X = 1031$

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

$Z = \frac{X - \mu}{\sigma}$

$1.96 = \frac{X - 1262}{118}$

$X - 1262 = 1.96*118$

$X = 1493$

Between 1031 and 1493.

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 1262}{118}$

$X - 1262 = -0.675*118$

$X = 1182$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 1262}{118}$

$X - 1262 = 0.675*118$

$X = 1342$

IQR:

1342 - 1182 = 160

7 0

3 years ago

The line graph shown below is of the amount of money astudent earns at a part time job, per hour. What is the students wage rate

xeze [42]

1) The two lines are perpendicular. (Correct choice: True)

2) The slope of the linear function is $ 10 per hour. (Correct choice: A)

<h3>How to analyze and interpret linear functions</h3>

Herein we must understand and analyze linear functions to find all required information from two exercises. The first exercise asks us to prove if the two lines seen are perpendicular and the second exercise asks us to calculate and interpret the slope of the linear function. Now we proceed to resolve each point:

Exercise 1

If the two lines are perpendicular, then the product of the two slopes must be equal to - 1. The value of slope can be found by secant line formula:

m · m' = - 1

[(1 - 2) / [0 - (-1)]] · [[-1 - (- 2)] / (1 - 0)]

(- 1 / 1) · (1 / 1)

- 1

The two lines are perpendicular. (Correct choice: True)

Exercise 2

In this part we must determine the rate of change of wage in time, in monetary units per time, which can be found by again by the secant line formula:

m = ($ 10 - $ 0) / (1 h - 0 h)

m = $ 10 per hour

The slope of the linear function is $ 10 per hour. (Correct choice: A)

To learn more on linear functions: brainly.com/question/21107621

#SPJ1

5 0

1 year ago