$x^2+4x+1=0\\\\\underbrace{x^2+2x\cdot2+2^2}_{(x+2)^2}-2^2+1=0\\\\use\ (a+b)^2=a^2+2ab+b^2\\\\(x+2)^2-4+1=0\\\\(x+2)^2-3=0\\\\(x+2)^2=3\iff x+2=\sqrt3\ or\ x+2=-\sqrt3\\\\\boxed{x=\sqrt3-2\ or\ x=-2-\sqrt3}$

7 0

3 years ago

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Evaluate -2x^2-4x+3 when x=-2

Misha Larkins [42]

Answer:

Step-by-step explanation:

A polynomial is sometimes easier to evaluate if it is first written in Horner form:

-2x^2 -4x +3 = (-2x -4)x +3

For x = -2, this is ...

(-2(-2) -4)(-2) +3 = 0(-2) +3 = 3

The value is 3 when x = -2.

8 0

2 years ago

Confirm that quadrilateral ABCD is a parallelogram. Measure and record the slope of each of its sides.

VMariaS [17]

Answer:

AB = 1.5

BC = 0

CD = 1.5

AD = 0

Step-by-step explanation:

Sample Answer for Plato

5 0

3 years ago

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