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vovikov84 [41]
3 years ago
5

HEEEELPPPPPPPPPPPPPP!!!!!!!!!!

Mathematics
1 answer:
Marianna [84]3 years ago
4 0
B- use Desmos it helps a lot!
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If s(x) = 2x2 + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =
Paladinen [302]

Answer:

\large\boxed{s(x)\cdot t(x)=2x^3+11x^2+8x-16}

Step-by-step explanation:

s(x)=2x^2+3x-4,\ t(x)=x+4\\\\s(x)\cdot t(x)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\s(x)\cdot t(x)=(2x^2+3x-4)(x+4)\\\\=(2x^2+3x-4)(x)+(2x^2+3x-4)(4)\\\\=(2x^2)(x)+(3x)(x)+(-4)(x)+(2x^2)(4)+(3x)(4)+(-4)(4)\\\\=2x^3+3x^2-4x+8x^2+12x-16\\\\\text{combine like terms}\\\\=2x^3+(3x^2+8x^2)+(-4x+12x)-16\\\\=2x^3+11x^2+8x-16

7 0
3 years ago
Factor –8x3 – 2x2 – 12x – 3 by grouping. What is the resulting expression?
xenn [34]
Easier if you first factor out the " - " sign.  Then you have:

–8x3 – 2x2 – 12x – 3    = -1(<span>8x3 + 2x2 + 12x +3).
</span>
Start with 12 + 3.  This factors to 3(4x+1).  Next, focus on 8x^3+2x^2.  This factors to 2x^2*(4x+1).  So, the binomial factor 4x+1 is common to the first two terms and the second two terms.  We get:  (4x+1) (  2x^2  + 3).

Now put the "-" sign back in, and we get   - (4x+1) ( 2x^2  + 3)    (answer)

Please note:  Use "^" to denote exponentiation.   2x2 is meaningless; it should be 2x^2.
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