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Fynjy0 [20]
3 years ago
12

Which of the following equations does not represent a linear relationship between x and y

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

A linear relationship is an equation that has a constant slope

The equation that does not represent a linear relationship is (b) y = 2x^2 + 5x

<h3>How to determine the non-linear relationship</h3>

A linear equation can take any of the following forms:

y = mx + b

y - y1 = m(x - x1)

Ax + By = c

Any form different from the above forms is not a linear equation

Using the above format as a guide, the equation that does not represent a linear relationship is (b) y = 2x^2 + 5x

Read more about linear relationships at:

brainly.com/question/15602982

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I think its Philadelphia hopes this helps...
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Jodie ran at an average speed of 10 km/h for 15 minutes.<br> How far did she run in km?
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Answer:

2.5 km

Step-by-step explanation:

15 minutes is

15 minutes * 1 hour/ 60 minutes = 1/4 hour

15 minutes = 1/4 of an hour

10 km/ hour * 1/4 hour = 10/4  km  = 2.5 km

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The number that is 10 less than 6
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The number (x) that is (=) 10 less than (-) 6

x = 6 - 10   Subtract
x = -4


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3 years ago
(0- (-3))×(-1+5)÷(2- (-2))<br><br><br><br>due today pls answer ​
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2 days late

Step-by-step explanation:

5 0
3 years ago
Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))
Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

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