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2 years ago

Which of the following equations does not represent a linear relationship between x and y

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

7 0

A linear relationship is an equation that has a constant slope

The equation that does not represent a linear relationship is (b) y = 2x^2 + 5x

<h3>How to determine the non-linear relationship</h3>

A linear equation can take any of the following forms:

y = mx + b

y - y1 = m(x - x1)

Ax + By = c

Any form different from the above forms is not a linear equation

Using the above format as a guide, the equation that does not represent a linear relationship is (b) y = 2x^2 + 5x

Read more about linear relationships at:

brainly.com/question/15602982

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May someone please help me with this :)

AlladinOne [14]

Answer: 16 pi or ≈50.27

Explanation: Formula for a cylinder:
V = pi r ^2 h
V = pi (2)^2 4
V = 4 pi (4)
V = 16pi

8 0

2 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

If x is equal to –2, then find the value of 3x² + 5x

attashe74 [19]

Answer:

Step-by-step explanation:

3*(-2)to power of 2 + 5*-2

= 3*4 + 5*-2

= 12 + -10 = 2

5 0

2 years ago

Jamie takes at random a counter from the bag and records the colour. Red : blue : green = 1:3:7 Jamie does this a number of time

Sonbull [250]

Answer: There are 249 times Jamie takes a counter from the bag.

Explanation:

Since we have given that

Ratio of colour of red to blue to green is 1:3:7.

Number of blue counters = 68

Let the total number of times Jamie does from the bag be x.

So, According to question,

$\frac{3}{11}\times x=68\\\\x=\frac{11}{3}\times 68\\\\x=249.33\\\\=249\ approx.$

Hence, there are 249 times Jamie takes a counter from the bag.

8 0

3 years ago

If I earn $15/hour and work for 20 hours/week, how much would I earn in one

choli [55]

Answer:

$1,200

Step-by-step explanation:

$15 x 20 = $300/week; $300 x 4 weeks = $1,200

6 0

1 year ago

Read 2 more answers