Question

A cat, also of weight wa, falls asleep on top of block

Answer 1

Answer: Let T be the tension of rope assuming negligible mass , T =( 2w_A)a/g ------- 1 (w_B) - T = (w_B)a/g ------- 2 ADD 1 and 2 w_B =( a/g)( 2w_A + w_B) a= g (w_B)/( 2w_A + w_B)