<span>1) We are given that PA = PB, so PA ≅ PB by the definition of the radius.
</span>When you draw a perpendicular to a segment AB, you take the compass, point it at A and draw an arc of size AB, then you do the same pointing the compass on B. Point P will be one of the intersections of those two arcs. Therefore PA and PB correspond to the radii of the arcs, which were taken both equal to AB, therefore they are congruent.
2) We know that angles PCA and PCB are right angles by the definition of perpendicular.
Perpendicularity is the relation between two lines that meet at a right angle. Since we know that PC is perpendicular to AB by construction, ∠PCA and ∠PCB are right angles.
3) PC ≅ PC by the reflexive property congruence.
The reflexive property congruence states that any shape is congruent to itself.
4) So, triangle ACP is congruent to triangle BCP by HL, and AC ≅ BC by CPCTC (corresponding parts of congruent triangles are congruent).
CPCTC states that if two triangles are congruent, then all of the corresponding sides and angles are congruent. Since ΔACP ≡ ΔBCP, then the corresponding sides AC and BC are congruent.
5) Since PC is perpendicular to and bisects AB, P is on the perpendicular bisector of AB by the definition of the perpendicular bisector.
<span>The perpendicular bisector of a segment is a line that cuts the segment into two equal parts (bisector) and that forms with the segment a right angle (perpendicular). Any point on the perpendicular bisector has the same distance from the segment's extremities. PC has exactly the characteristics of a perpendicular bisector of AB. </span>
Answer:
15
Step-by-step explanation:
5/6 * 18
Rearranging
5 * 18/6
5 *3
15
The area of only one base was added. The first term should have a factor of 2.
Hello!
To find the y-values of the given ordered pairs, substitute the x-values into the equation, y = log₂ x.
y = log₂ 1/2, y = -1
y = log₂ 1, y = 0
y = log₂ 2, y = 1
y = log₂ 4, y = 2
y = log₂ 8, y = 3
y = log₂ 16, y = 4
Therefore, the ordered pairs of y = log₂ x is: {(1/2, -1), (1, 0), (2, 1), (4, 2), (8, 3), (16, 4)}.
Answer: Choice D)
F(x) > 0 over the inverval (-infinity, -4)
Translation: The y or f(x) values are positive whenever x < -4.
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Further Explanation:
Recall that y = f(x), so if we say something like f(x) < 0 then we mean y < 0. Choice A is false because points on the curve to the left of x = -4 have positive y coordinates. Similar reasoning applies to choice B as well.
Choice C is false because while the interval (-infinity, -4) is above the x axis, the portion from x = -4 to x = -3 is below the x axis.
Choice D is true because everything to the left of x = -4 is above the x axis. Pick any point on the blue curve that is to the left of x = -4. This point will be above the horizontal x axis. Keep in mind that the parenthesis notation attached to the -4 means we dont include -4 as part of the interval.
