Help me pls pls pls

Mathematics

1 answer:

Sergeeva-Olga [200]2 years ago

7 0

Answer:

ANSWER IS C

Step-by-step explanation:

adj = 3

opp = 4

tanx = $\frac{opp}{adj}$

tan C = $\frac{4}{3}$

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const2013 [10]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

boxes of a whole wheat linguine are on sale this week for 30% off the original price. they cost $1.50 when they are not on sale.

allochka39001 [22]

30% of $1.50 is 0.45 and if it's on sale you subtract from original price
so 1.50 - 0.45
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2 years ago

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Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$