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matrenka [14]
2 years ago
9

Can you help me solve for x

Mathematics
1 answer:
astraxan [27]2 years ago
3 0
X=2 I believe but I need to keep typing to make it longer
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The slope of the tangent line for the curve r=2 cos(3 theta) where theta = pi/6 is.
Phantasy [73]

as you already know, the slope of the tangent line is simply the derivative of the function, so

r=2cos(3\theta )\implies \cfrac{dr}{d\theta }=2\stackrel{chain~rule}{\left[ -sin(3\theta )\cdot 3 \right]} \\\\\\ \left. \cfrac{dr}{d\theta }=-6sin(3\theta ) \right|_{\theta =\frac{\pi }{6}}\implies -6sin\left( 3\cdot \frac{\pi }{6} \right)\implies -6sin\left( \frac{\pi }{2} \right)\implies -6

7 0
2 years ago
Kaya used 7 cups of flour to bake 5 cakes how much flour on average did she put in each cake ? Write your answer as a decimal.
Ksju [112]
The answer would be 1.4, because 7 cups into 5 cakes equals 1.4.

Hope this helps ya
3 0
3 years ago
Read 2 more answers
Determine the quadrant when the terminal side of the angle lies according to the following conditions: cos (t) < 0, csc (t) &
Bess [88]

Answer:

The angle is in the second quadrant.

Step-by-step explanation:

The cosecant of an angle is the same as the reciprocal of the sine of that angle. In other words, as long as \sin (t) \ne 0,

\displaystyle \csc t = \frac{1}{\sin t}.

Therefore, \csc(t) > 0 is equivalent to \sin (t) > 0.

Consider a unit circle centered at the origin. If the terminal side of angle t intersects the unit circle at point (x,\, y), then

  • \cos (t) = x, and
  • \sin(t) = y.

For angle t,

  • x = \cos(t) < 0, meaning that the intersection is to the left of the y-axis.
  • y = \sin(t) > 0, meaning that the intersection is above the x-axis.

In other words, this intersection is above and to the left of the origin. That corresponds to second quadrant of the cartesian plane.

6 0
3 years ago
49°<br> Solve for 42.<br> 2 = [?]<br> 44/62
Brrunno [24]

Answer:

∠2 = 41°

Step-by-step explanation:

∠2 + 49° + 90° = 180°

∠2 + 139° = 180°

∠2 = 180° - 139°

∠2 = 41°

5 0
3 years ago
Read 2 more answers
Someone plz help me with this
Phoenix [80]

Answer:

5y^{6}\sqrt{2}

Step-by-step explanation:

We want to  simplify:

\sqrt{50y^{12}}

We rewrite as:

\sqrt{2\times25 \times (y^{6})^2}

We split the radical sign to obtain:

\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}

Simplify the square root for the perfect squares to get:

5y^{6}\sqrt{2}

Therefore the simplified form is: 5y^{6}\sqrt{2}

8 0
3 years ago
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