A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 12 inches. If the lizard is 8 inches from a point of tangency, find the direct distance between the lizard and the cactus (x). If necessary, round to the hundredths place.
1 answer:
We will use the Pythagorean theorem:2.42 in
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Answer:
A = -2.2
B = -1.7
C = 1.87
D = 19.97
Step-by-step explanation:
A = 7.4 - 9.6 = -2.2
B = -2.2 + 0.5 = -1.7
C = -1.1(-1.7) = 1.87
D = 18.1 + 1.87 = 19.97
32 x4 = 128 ftFinal Answer: 1,536 inches
Answer:38
Step-by-step explanation:
Answer:
3.14
Step-by-step explanation:
Area of a corcle is sexpressed as';
A = πr²
π = A/r²
π = 78.54/5²
π = 78.54/25
π = 3.1416
When the area is divided by radius the required constant is 3.14
Answer:
2 ± i
Step-by-step explanation:
by 5, I assume you mean +5
x² - 4x + 5 = 0
x = (-b±(√(b²-4ac)) / 2a
x = (4 ± (√(16 - 20)) / 2
x = (4 ± (√(-4)) / 2
√-4 = √4√-1 which is 2i
x = (4 ± 2i) / 2
x = 2 ± i
