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noname [10]
3 years ago
15

My teacher gave me the brain teaser and ive been trying to figure it out can someone help she wants me to find 2 answers for it.

Mathematics
1 answer:
Masja [62]3 years ago
7 0
2^5 + (4 + 3 + 1) = 40

((5 x 3) + (4 + 1)) x 2 = 40
You might be interested in
Start 7:10 elapsed end 8:30
Anettt [7]
It has been 1 hour and 20 minutes.

HOW I FOUND MY ANSWER:

7:10 to 8:10 = 1 hour

8:10 to 8:30 = 20 minutes

(1 hour + 20 minutes = 1 hr and 20 min.)

HOPE THIS HELPED
:)
3 0
3 years ago
Please help :c
miss Akunina [59]

Answer: $17.55

Step-by-step explanation:

36 x 0.65 = $23.40 total for all cookies

($23.40/1) x (3/4) = (70.2/4)

70.2 divided by 4 = $17.55

or

$23.40 x .75 = $17.55

4 0
2 years ago
Solve the system of equations.<br><br> −4x+3y=−2<br> y=x−1<br><br> x-<br> y-<br> ​
Kobotan [32]

Answer: x=  -1

               y= -2

Step-by-step explanation:

-4x+3y= -2

y=x-1

-------------------

-4x+3(x-1)= -2

-4x+3x-3= -2

-x=1

x= -1

y=-1-1

y=-2

6 0
3 years ago
Read 2 more answers
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!
alexandr1967 [171]

Answer:

D.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
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