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frez [133]
3 years ago
9

If 3(d+1)=4(d–2) then what is the value of 5(d–2)

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

Answer:

5(d - 2) = 45

Step-by-step explanation:

Solve the given equation for d

3(d + 1) = 4(d - 2) ← distribute parenthesis on both sides

3d + 3 = 4d - 8 ( subtract 3d from both sides )

3 = d - 8 ( add 8 to both sides )

11 = d

Then

5(d - 2) = 5(11 - 2) = 5(9) = 45

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(995/2) ÷ 2 = 248.75

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What is the name of the expression under the radical symbol in a radical function?
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An expression is defined as a set of numbers, variables, and mathematical operations. The name of the expression under the radical symbol in a radical function is called a radicand.

<h3>What is an Expression?</h3>

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5 0
2 years ago
Solve 5x = 2 written a afrction inits simplest form
Elden [556K]

Answer:

x = 2/5

General Formulas and Concepts:

Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Write equation</u>

5x = 2

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Divide both sides by 5:          x = 2/5

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution</em>.

  1. Substitute:                    5(2/5) = 2
  2. Multiply:                        10/5 = 2
  3. Divide:                           2 = 2
4 0
3 years ago
It always confuses me when they make me do the baby steps
fgiga [73]

A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.

3x-y=0 → 2(3x-y=0) = 6x - 2y = 0

5x+2y=22


The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22


B. So now we combine them:

6x - 2y = 0

+ + +

5x + 2y = 22

= = =

11x + 0 = 22 ← The answer


C. Now that we have the equation 11x = 22, we solve for x

11x = 22 ← Divide both sides by 11

x = 2 ← The answer


D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:

5(2)+2y = 22

10 + 2y = 22

2y = 12

y = 6


<u>Therefore, the solution to this problem is x = 2 and y = 6</u>


5 0
3 years ago
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