log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
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Answer:
probability of the personal information on the direction of the personal information to my house
{8, 16, 24, 32}int.{16, 32, 48}={16, 32}
Y = x^2 + 8x - 3
y = x^2 + 8x + (8/2)^2 - 3 - (8/2)^2
y = x^2 + 8x + 16 - 3 - 16
