Answer:
6.11km/hr
Step-by-step explanation:
Let the speed that Kelli swims be represented by Y
Speed of the river = 5km/hr
Distance = Speed × Time
Kelli swam upstream for some distance in one hour
Swimming upstream takes a negative sign, hence:
1 hour ×( Y - 5) = Distance
Distance = Y - 5
She then swam downstream the same river for the same distance in only 6 minutes
Downstream takes a positive sign
Converting 6 minutes to hour =
60 minutes = 1 hour
6 minutes =
Cross Multiply
6/60 = 1/10 hour
Hence, Distance =
1/10 × (Y + 5)
= Y/10 + 1/2
Equating both equations we have:
Y - 5 = Y/10 + 1/2
Collect like terms
Y - Y/10 = 5 + 1/2
9Y/10 = 5 1/2
9Y/ 10 = 11/2
Cross Multiply
9Y × 2 = 10 × 11
18Y = 110
Y = 110/18
Y = 6.1111111111 km/hr
Therefore, Kelli's can swim as fast as 6.11km/hr still in the water.
Answer:
See the proof below
Step-by-step explanation:
Let the line AB be a straight line on the parallelogram.
A dissection of the line (using the perpendicular line X) gives:
AY ≅ BX
Another way will be using the angles.
The angles are equal - vertically opposite angles
Hence the line AY ≅ BX (Proved)
Answer:
<h2>7</h2>
Step-by-step explanation:
here 7×7 = 49
So the square root of 49 is 7.
Hope it helps you!!
#IndianMurgaツ
Please mark me brainless :)
Answer:
3:40 p.m.
Step-by-step explanation:
Add 74 minutes to 1:25 p.m.; the improperly formed result witll be 1:99 p.m.; to express this properly, add 1 hour to this time and subtract 60 minutes from it:
2:39 p.m. (time at which Avery gets off the bus)
If Avery walked 61 minutes to get home and we want to know what time she arrived, we add 61 minutes to 2:39 p.m., obtaining 2:100 p.m., which must in turn be re-written as 3:40 p.m.
Avery arrived home at 3:40 p.m.
Note: another way in which to do this problem is to add 74 minutes and 61 minutes, obtaining 135 minutes, and then adding 135 minutes to 1:25 p.m. and making the necessary adjustments to the result:
1:25 p.m. + 135 minutes = 1:160 p.m., or (recognizing that 120 min = 2 hours)
3:40 p.m.
