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2 years ago

How to Simplify: (a + 2)(3a - 1')

Mathematics

1 answer:

IrinaVladis [17]2 years ago

3 0

3a to the power of 2 plus 5a minus 2

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The cost of a taxi ride is represented by the function c(m)=2m+4, where m is the number of miles traveled. What is the cost per

deff fn [24]

Answer:

Step-by-step explanation:

We have: The cost of a taxi ride is represented by the function c(m)=2m+4

Plug 1 mile into "m" of the function c(m)=2m+4

So, we have c (1) = 2 ˣ 1 + 4 = 6

Thus, The cost per mile of the cab is $6.

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2 years ago

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Find the zeros of f(x)=-3x^3+6x+5.

Tasya [4]

Answer:

x = 1.723

Step-by-step explanation:

The zeros of a function f(x) are the points where the function crosses the x-axis. At these points, the function will have a value of zero, that is;

f(x) = 0

We simply graph the function and determine the points where it crosses the x-axis. From the attachment, f(x) crosses the x-axis at;

x = 1.723

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3 years ago

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Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation? Solve x2 = 12x – 15 by completing the s

Svetlanka [38]

Answer: $6+\sqrt{21}\ \text{and}\ 6-\sqrt{21}$

Step-by-step explanation:

Given

Quadratic equation is

$x^2-12x+15=0$

Solving by completing the square method

$\Rightarrow x^2-2\cdot 6\cdot x+15=0\\\text{add and subtract 36}\\\Rightarrow x^2-2\cdot 6\cdot x+15+36-36=0\\\Rightarrow x^2-2\cdot 6\cdot x+36+(-36+15)=0\\\text{using}\ (a-b)^2=a^2+b^2-2ab\\\Rightarrow (x-6)^2-21=0\\\Rightarrow (x-6)^2=21\\\Rightarrow x-6=\pm \sqrt{21}\\\Rightarrow x=6\pm \sqrt{21}$

The solution set of the equation is $6+\sqrt{21}\ \text{and}\ 6-\sqrt{21}$

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2 years ago

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One staple weighs 31 milligrams. If a box of staples holds 250 staples, how many grams of staples does the box hold?

lilavasa [31]

Answer:

7.75

Step-by-step explanation:

1 mg = 0.001 g

31 mg * 0.001 = 0.31 grams per staple

0.31 g * 250 = 7.75 grams per 250 staples

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2 years ago

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Which equation is equivalent to √x^2+81 = x+10

jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

$\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2$