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Ksivusya [100]
2 years ago
12

Y = -2x2 + 10 y = -2x – 2

Mathematics
2 answers:
soldier1979 [14.2K]2 years ago
6 0

Answer:

Step-by-step explanation:

hello :

y = -2x² + 10

y = -2x – 2

-2x²+10 = -2x-2

2x²-2x -12 = 0

x²-x-6 = 0

(x-3)(x+2)=0

x-3=0 or x+2=0

x=3 or x=-2

but  y = -2x-2

if ; x=3     y = -2(3)-2 =-8

if : x=-2     y=-2(-2)-2=2

two solutions : (3 , -8)  and (-2 , 2)

34kurt2 years ago
4 0

Answer:

x = 6

y = - 14

Step-by-step explanation:

\left \{y=-2x2 + 10y} \atop {y=-2x -2}} \right.

  1. -2x × 2 + 10 = - 2x - 2
  2. x = 6
  3. y = -2 × 6 - 2 = - 14
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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

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=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

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