What is the length of the midsegment of this trapezoid? Enter your answer in the box.
1 answer:
You might be interested in
Answer:
15°
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
Answer:
C, D, E, F
Step-by-step explanation:
Remember y=mxb?
m is slope and b is y-intercept
so y=2/7x-9
Remember that slope is RISE/RUN so for every 2 squares that you go up, you go 7 squares to the right.
Also remember that since your graph is going thru your Cartiesian Plane in quadrent 4, your y value in your ordered pairs will most probably be a negative.
Please see the image to help you viualize this.
