a right angle can have at least 2
There are four solutions for the <em>trigonometric</em> equation 2 · cos x = 4 · cos x · sin² x are x₁ = π/4 ± 2π · i, x₂ = 3π/4 ± 2π · i, x₃ = 5π/4 ± 2π · i and x₄ = 7π/4 ± 2π · i,
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<h3>How to solve a trigonometric equation</h3>
In this problem we must simplify the <em>trigonometric</em> equation by both <em>algebraic</em> and <em>trigonometric</em> means and clear the variable x:
2 · cos x = 4 · cos x · sin² x
2 · sin² x = 1
sin² x = 1/2
sin x = ± √2 /2
There are several solutions:
x₁ = π/4 ± 2π · i, 
x₂ = 3π/4 ± 2π · i, 
x₃ = 5π/4 ± 2π · i, 
x₄ = 7π/4 ± 2π · i, 
There are four solutions for the <em>trigonometric</em> equation 2 · cos x = 4 · cos x · sin² x are x₁ = π/4 ± 2π · i, x₂ = 3π/4 ± 2π · i, x₃ = 5π/4 ± 2π · i and x₄ = 7π/4 ± 2π · i,
.
To learn more on trigonometric equations: brainly.com/question/27821667
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Answer:
4
Step-by-step explanation:
Any polynomial of degree n has n roots
but we may need to use complex numbers
This is a 4th degree polynomial therefor:
4 roots

Since both y squared and 6y have a common factor of y, can put that to the side and divide both the y squared and 6y to get the second step of the work shown above. Separate both the y on the outside of the parentheses and the numbers within the parentheses and set them both equal to 0 as shown in step 3 of the work shown above. Finally solve for y as you would normally. Those two number in step 4 should be your final answer.
Answer:
(c) Equilateral Step-by-step explanation: