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nirvana33 [79]
3 years ago
7

Someone please help me

Mathematics
1 answer:
Dovator [93]3 years ago
5 0
<h3>Answer:  B) 2</h3>

=========================================================

Explanation:

Take away the four white small squares on the left side. To balance things out, you have to add 4 black squares to the right side.

Also, take away the two white long rectangles from the right side. To balance this out, you have to add 2 gray long rectangles to the left side.

You should have:

  • 5 gray rectangles, and no squares (of any color) on the left side
  • 10 black squares, no long rectangles (of any color), on the right side

From here you'll group up the 10 black squares so that you'll have 2 black squares per gray rectangle.

This means the solution is 2.

-------------------------------------

If you're curious about the algebraic way to solve, then you could do this:

3x-4 = -2x+6

3x+2x = 6+4

5x = 10

x = 10/5

x = 2

This method doesn't require us to use the visual model.

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Someone please help out
exis [7]

Answer:

39+0.15m \leqslant 50

Step-by-step explanation:

From the question, Diana wants her total bill to be less than $50.

Diana pays a fixed monthly bill of

$39 for her mobile phone and an additional

$0.15 per minute for phone internet service.

The bill Diana pays for m minutes of using the internet is $0.15m in a month.

The total monthly bill becomes,

39+0.15m

The maximum bill she wants to pay is $50.

\implies39+0.15m \leqslant 50

This inequality can be solved to determine the number of available minutes.

4 0
3 years ago
How can you get the variable alone in 84+c=111
VLD [36.1K]
Subtract 84 on the other side of the equal sign and bring down c and the answer you get from 111 - 84.
4 0
3 years ago
Read 2 more answers
A dinâmica da população mudial<br>resumo ​
uysha [10]
So basically you need to ......

Hope it helps
4 0
3 years ago
Simplify the equation √5 + √5​
Ronch [10]

You can treat sq rt5 as a variable even though it is a number:

Ex: x + x = 2x

Or as a number: 5 + 5 = 10 or 2(5)

So sq rt5 + sq rt5 = 2sq rt5

4 0
3 years ago
Find the range of h(x)=x^2 + 2x - 5 when the domain is {-4,-2,0,2}
Dimas [21]

The range is: {3,-5}

Step-by-step explanation:

Given

h(x)=x^2 + 2x - 5

We will get the range by putting the values given in domain in the function

Putting x=-4

h(-4)=(-4)^2 + 2(-4) - 5\\=16-8-5\\=16-13\\=3

Putting x=-2

h(-2)=(-2)^2 +2(-2) - 5\\=4-4-5\\=0-5\\=-5

Putting x=0

h(0)=(0)^2 + 2(0) - 5\\=0+0-5\\=-5\\

Putting x=2

h(2)=(2)^2 + 2(2) - 5\\=4+4-5\\=8-5\\=3

The range is: {3,-5}

Keywords: Functions, Range

Learn more about range at:

  • brainly.com/question/5528742
  • brainly.com/question/5533462

#LearnwithBrainly

7 0
3 years ago
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