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Jet001 [13]
3 years ago
8

HELP IVE BEEN ON THIS QUESTION FOR SO LONG PLS ISTG IM SO STUPID AND IM FAILING PLEASE HELP LMKAKAKAJOAKS

Mathematics
1 answer:
dangina [55]3 years ago
7 0

Answer:

Step-by-step explanation:

.

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Karen has $600. She spent $240 on clothes. What percentage of money did she have left?
Rudiy27

Answer: She had 60% of the money left

Step-by-step explanation:

240/600=0.4

0.4 = 40%

100%-40%=60%

7 0
3 years ago
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Im trying to pass the hardest quiz in the world(will give brainliest) the first question is
Ymorist [56]
Whatever your color eyes are


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3 years ago
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Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

5 0
3 years ago
Princess Kate is trying on wedding dresses. Each dress is too small, fits well, or is too big. Princess Kate estimates that 40%
Tcecarenko [31]
The answer would be 35%
8 0
3 years ago
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H(t) = -t + 3; Find h(-5)
Anastasy [175]

Answer:

8

Step-by-step explanation:

h(t) = -t + 3;

h(-5)

Let t = -5

h(-5) = - -5 +3

       = 5+3

       = 8

7 0
3 years ago
Read 2 more answers
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