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3 years ago

Can someone please help me ? i will mark brainliest plesase

Mathematics

2 answers:

AfilCa [17]3 years ago

6 0

Answer:

B. oBtUsE

Step-by-step explanation:

hope this helps

pew pew.

____ [38]3 years ago

5 0

Answer:

C. Obtuse

Step-by-step explanation:

An obtuse triangle is a triangle with one obtuse angle and two acute angles.

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use a protractor to find the measure of each angle. Write each angle and its measure in a box ordered by the measure of the angl

NikAS [45]

Answer:

Part 1) and Part 2) in the procedure

Step-by-step explanation:

step 1

Find the measures of angles

we know that

The sum of the angles A, B and C must be equal to 360 degrees

Using a protractor

The measures of angles are

∠A=140°

∠B=100°

∠C=120°

step 2

Ordered the measures of the angles from least to greatest

1) ∠B=100°

2) ∠C=120°

3) ∠A=140°

7 0

4 years ago

What is dilation and can someone explain in a easy way

gogolik [260]

dilation is when a shape changes size, from small to big or big to small.

4 0

3 years ago

Read 2 more answers

I want help its urgent!!! (iv), (v), (vi) Questions

Artist 52 [7]

Solution:

iv) Given equation: $x^{2} - y^{2} - 4x - 2y + 3$

Since we are given two variables, we need to split the original expression into two quadratic expressions as

$x^{2} - 4x + 4 - y^{2} - 2y - 1$

Factoring x first:

$x^{2} - 4x + 4 =$ $x^{2} - 2x - 2x + 4$

= $x (x - 2) - 2 (x-2)$

= $(x-2)(x-2)$

$= (x-2)^{2}$

Factoring y now:

$-y^{2} - 2y - 1 = -1(y^{2} + 2y + 1)$

= $-1(y^{2} + y + y + 1)$

= $-1[ y(y+1) + 1(y+1)]$

= $-1 [(y+1)(y+1)]$

= $(y+1)(-y-1)$

Therefore, the original expression becomes

$(x-2)^{2}+(y+1)(-y-1)\\or \\(x-2)(x-2) + (y+1)(-y-1)$

7 0

3 years ago

Underline all the ordered pairs (x,y) that are solutions to the equation y=2x+1.

Romashka [77]

Answer:

(3,7) (7,3) (−1,14) (0,1) (12,25)

(5,11) (0,12) (1,8) (12,0) (−1,−1)

Step-by-step explanation:

We have the following function:

$y = 2x+1$ .

We are going to check if each ordered pair is a solution.

(3,7)

If when $x = 3, y = 7$ , it is a solution.

$y = 2x + 1 = 2(3) + 1 = 7$

This ordered pair is a solution.

(7,3)

If when $x = 7, y = 3$ , it is a solution.

$y = 2x + 1 = 2(7) + 1 = 15$

This ordered pair is not a solution.

(-1,14)

If when $x = -1, y = 14$ , it is a solution.

$y = 2x + 1 = 2(-1) + 1 = -1$

This ordered pair is not a solution.

(0,1)

If when $x = 0, y = 1$ , it is a solution.

$y = 2x + 1 = 2(0) + 1 = 1$

This ordered pair is a solution.

(12,25)

If when $x = 12, y = 25$ , it is a solution.

$y = 2x + 1 = 2(12) + 1 = 25$

This ordered pair is a solution.

(5,11)

If when $x = 5, y = 11$ , it is a solution.

$y = 2x + 1 = 2(5) + 1 = 11$

This ordered pair is a solution.

(0,12)

If when $x = 0, y = 12$ , it is a solution.

$y = 2x + 1 = 2(0) + 1 = 1$

This ordered pair is not a solution.

(1,8)

If when $x = 1, y = 8$ , it is a solution.

$y = 2x + 1 = 2(1) + 1 = 3$

This ordered pair is not a solution.

(12,0)

If when $x = 12, y = 0$ , it is a solution.

$y = 2x + 1 = 2(12) + 1 = 25$

This ordered pair is not a solution.

(-1,-1)

If when $x = -1, y = -1$ , it is a solution.

$y = 2x + 1 = 2(-1) + 1 = -1$

This ordered pair is a solution.

3 0

3 years ago

What is the domain of the step function f(x) = ⌈2x⌉ – 1?

maxonik [38]

Domain is what you can put in

the domain for most functions is ALL REAL NUMBERs
except for those that violate the dividing by zero thingummy
example
if yu had
f(x)=x+2
domain is all real numbers
f(x)=2/x
domain is all real numbers except for 0 since cannot divide by 0
f(x)=2(x-4)
domain is all real numbers except for 4

so answer is {x|x is a real number}

6 0

3 years ago

Read 2 more answers