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balu736 [363]
3 years ago
8

1.24 to percent convertingbetween percents,decimals and fractions

Mathematics
1 answer:
trapecia [35]3 years ago
3 0

As a percent : 124%

As mixed fraction : 1 6/25

As improper fraction : 31/25

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I really need help with this ... I hope someone can help!
viva [34]

9514 1404 393

Answer:

  ∠B = 53°

  ∠C = 127°

  ∠D = 127°

Step-by-step explanation:

The trapezoid is isosceles, as indicated by the hash marks on sides AD and BC. This means it is symmetrical about the vertical center-line. Angles on the right will have the same measures as the symmetrical angles on the left.

So, you know immediately that ∠B = ∠A = 53°.

Because AB ║ DC, ∠A and ∠D are supplementary. That is, ...

  ∠D = ∠C = 180° -53°

  ∠D = ∠C = 127°

4 0
3 years ago
Use the following information for problems 1-3.
sertanlavr [38]

Answer:

the scores on the final exam were normally distributed, with a mean of 85, and a standard deviation of five.

Step-by-step explanation:

5 0
3 years ago
Can someone please help me with this question I’m stuck
Liono4ka [1.6K]

so i think its 97 degrees try that!

5 0
4 years ago
Read 2 more answers
Twice as many students go to the park than to the theater. Five more students go to the theater than to the museum. If 16 studen
Lemur [1.5K]

Answer:

3 students

Step-by-step explanation:

Twice as many students go to the park than to the theater :

Let number who go the theater = t

Number who goes to park = 2t

5 more students go to the theater than to the museum

Number who goes to museum = t - 5

If number of students who goes to park = 16

How many students goes to the museum :

2t = 16

t = 16/2

t = 8

Number who goes to museum = t - 5

t - 5 = 8 - 5 = 3

Hence, number of students who goes to the museum = 3

4 0
3 years ago
Factorise tis please.<br> <img src="https://tex.z-dn.net/?f=%20%28x%2B3%29%5E%7B2%7D%20%2B2%28x%2B3%29" id="TexFormula1" title="
Otrada [13]
\displaystyle \boxed{(a+b)=a^2+2ab+b^2} \\ \\ (x+3)^2+2(x+3)= \\ x^2+2 \cdot x \cdot 3 +3^2+2x+6 = \\ x^2+6x+9+2x+6= \\ x^2+8x+15= \\ \\ \Delta= b^2-4ac \\ \Delta=8^2-4 \cdot1 \cdot15 \\ \Delta=64-60=4 \\ \\ \\ X_{1,2}= \frac{-b\pm \sqrt{\Delta} }{2a} =  \frac{-8\pm2}{2} = \\ \\X1=5 \\ X2=3
5 0
4 years ago
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