if the compound interest on a sum for 2 years at 4% p.a. is ₹408, then the simple interest on the same sum at the same rate and
1 answer:
Given that:
CI = ₹408
years = 2 years
Rate of interest = 4%
A = P{1+(R/100)}^
A-P = p{1+(R/100)}^n - P
I = P[1+(R/100)}^n - 1]
408 = P[{1+(4/100)²} - 1]
= P[{1+(1/25)²} - 1]
= P[(26/25)² - 1]
= P[(676/625) - 1]
= P[(676-625)/625]
408 = P(51/625)
P = 408*(625/51)
= 8*625 = 5000
Sum = 5000
Simple Interest (I) = (P*R)/100
= 5000*2*(4/100)
= 50*2*4 = 400
From the given above options, option (a) ₹400 is your correct answer.
You might be interested in
Answer:
Option (4)
Step-by-step explanation:
Equation of a line passing through a point and with slope 'm' is,
y - y₁ = m(x - x₁)
Given → Slope 'm' = -2
Point through which the line is passing is (-1, -2)
x₁ = -1 and y₁ = -2
Therefore, equation will be,
y + 2 = -2(x + 1)
y = -2x - 2 - 2
y = -2x - 4
Option (4) is the correct option.