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Mariulka [41]
4 years ago
9

Triangle ABC has a height of 8 cm and an area of 42cm². Calculate the length of BC.

Mathematics
2 answers:
german4 years ago
5 0

BC must be base then

Area: 42cm²

Height: 8cm

Base: BC

1/2 × b × h = 42

1/2 × b × 8 = 42

b = 42/4

b = 21/2

BC = 21/2 or 10 1/2

Or 10.5cm

Must click thanks and mark brainliest

Tcecarenko [31]4 years ago
3 0

BC must be base

  • Height=8cm
  • Area=42cm^2

We know

\boxed{\sf Area_{(Triangle)}=\dfrac{1}{2} Height\times Base}

\\ \sf\longmapsto 42=\dfrac{1}{2}8BC

\\ \sf\longmapsto 4BC=42

\\ \sf\longmapsto BC=\dfrac{42}{4}

\\ \sf\longmapsto BC=10.5cm

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a_1=-20,\ a_3=-15\\\\2d=a_3-a_1\to 2d=-15-(-20)\to2d=-15+20\to2d=5\to d=2.5\\\\a_n=a_1+(n-1)d\to a_n=-20+(n-1)(2.5)=-20+2.5n-2.5=2.5n-22.5\\\\a_2=2.5(2)-22.5=5-22.5=-17.5\\\\a_4=2.5(4)-22.5=10-22.5=-12.5\\\\a_6=2.5(6)-22.5=15-22.5=-7.5

<u>n   |    1     |   2    |   3   |   4   |   5    |   6   |</u>

f(n)|  -20  | -17.5 |  -15  |-12.5|  -10  | -7.5 |

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a_1=123,\ a_2=131\\\\d=a_2-a_1\to d=131-123=8\\\\a_n=a_1+(n-1)d\to a_n=123+(n-1)(8)=123+8n-8=8n+115\\\\a_3=8(3)+115=24+115=139\\\\a_5=8(5)+115=40+115=155\\\\a_6=8(6)+115=48+115=163

<u>n   |    1     |   2    |   3   |   4   |   5    |   6   |</u>

f(n)|  123  |  131   | 139 | 147  |  155  | 163 |

First term: 123      Common Difference: 8

Explicit Rule:  a_n=8n+115       Recursive Rule: a_1=20,\ a_n=a_{n-1}+8

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