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Igoryamba
3 years ago
9

What is the value of x?

Mathematics
2 answers:
pantera1 [17]3 years ago
7 0

x=9 because the triangle is equilateral which means every side is equal to 60. When you do the math you get 7x-3=60 which is 7x=63 and 63/7=9

Yakvenalex [24]3 years ago
3 0

x = 9

The triangle has all 3 sides congruent and is thus an equilateral triangle.

Each angle = 60°

equate 7x - 3 = 60 and solve for x ( add 3 to both sides )

7x = 63 (divide both sides by 7 )

x = \frac{63}{7} = 9



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(\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2

                           + 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5

5C_0(\frac{1}{ax})^5(2ax^2)^0  =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1  = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\

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The fourth term of the expansion has the constant a,

the coefficient of a is 80x⁴

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