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Answer:
The probability that you will get a sum of 4 before you get a sum of 5 is
Step-by-step explanation:
Given : If you roll two fair dice repeatedly.
To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?
Solution :
When two dice are rolled the outcomes are
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Total number of outcomes = 36
Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3
The probability that you will get a sum of 4 before you get a sum of 5 is
Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is
Answer:
$400
Step-by-step explanation:
Given at the end of 2017 estimated warranty payable is $ 1,300
Also given that During 2018, Roy Electric made sales of $ 140,000 and expects product warranties to cost the company 1 percent of the sales
The warranties made in the year 2018 is
Given that the company already paid $2300 warranties so
Total warranties payable are 1300 + 1400 - 2300 = $400