All categories

2 years ago

What is the slope of y=-x+15

Mathematics

2 answers:

NikAS [45]2 years ago

7 0

-1

Step-by-step explanation:

y=mx+b

m=slope and b= point where line crosses y axis.

in our case slope is -1, because -x=-1x (mx)

Viefleur [7K]2 years ago

3 0

Answer:

35y

Step-by-step explanation:

You might be interested in

Put the following equation in shape intercept form y-2=-3(x-5)

Damm [24]

Answer:

y = -3x + 17

Step-by-step explanation:

In this question, you have to put the given equation into slope intercept form.

Slope-intercept form: y = mx + b

Solve:

y - 2= -3(x - 5)

Use the distributive property to distribute the -3 to the variables inside the parenthesis.

y - 2 = -3x + 15

Add 2 to both sides to get "y" by itself.

y = -3x + 17

The slope intercept form of the line would be y = -3x + 17

7 0

3 years ago

Find the value of x and the value of y.

stepladder [879]

Answer:

You haven't given enough information to answer the question.

Step-by-step explanation:

4 0

3 years ago

A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. to 2 decimal place

Kazeer [188]

The rate of change of the angle of elevation when the firework is 40 feet above the ground is 0.12 radians/second.

First we will draw a right angle triangle ΔABC, where ∠B = 90°

Lets, assume the height(AB) = h and base(BC)= x

If the angle of elevation, ∠ACB = α, then

tan(α) = $\frac{AB}{BC} = \frac{h}{x}$

Taking inverse trigonometric function, α = tan⁻¹ ( $\frac{h}{x}$ ) .............(1)

As we need to find the rate of change of the angle of elevation, so we will differentiate both sides of equation (1) with respect to time (t) :

$\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}$

Here, the firework is launched from point B at the rate of 10 feet/second and when it is 40 feet above the ground it reaches point A,

that means h = 40 feet and $\frac{dh}{dt}$ = 10 feet/second.

C is the observer's position which is 50 feet away from the point B, so x = 50 feet.

$\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512$

= 0.12 (Rounding up to two decimal places)

So, the rate of change of the angle of elevation is 0.12 radians/second.

5 0

3 years ago

evelyn rode her horse along a triangular path. The distance she traveled south was 5 times the distance she traveled east. Then

cricket20 [7]

(5x)^2 + x^2 = c^2

25x^2 + x^2 =c^2

sqrt 26 x ^ 2 = sqrt c^2

x sqrt 26= c

so answer is 6x + x sqrt 26

8 0

3 years ago

What is the vertex of this parabola? y= 2x² + 4x +5

uranmaximum [27]

Answer:

vertex = (- 1, 3 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

y = 2x² + 4x + 5 ← is in standard form

with a = 2, b = 4, then

$x_{vertex}$ = - $\frac{4}{4}$ = - 1

Substitute x = - 1 into the equation for corresponding value of y, that is

y = 2(- 1)² + 4(- 1) + 5 = 2 - 4 + 5 = 3

vertex = (- 1, 3 )

6 0

3 years ago