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amm1812
3 years ago
10

What is the slope of y=-x+15

Mathematics
2 answers:
NikAS [45]3 years ago
7 0

-1

Step-by-step explanation:

y=mx+b

m=slope and b= point where line crosses y axis.

in our case slope is -1, because -x=-1x (mx)

Viefleur [7K]3 years ago
3 0

Answer:

35y

Step-by-step explanation:

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Which of the following sets contain all roots of the polynomial
Zarrin [17]

All these given roots are contained in option C.

The given equation is :

9x^{3}+9x^{2}-4x-4=0

9x^{2}(x+1)-4(x+1)=0

(9x^{2}-4)(x+1)=0

9x^{2}-4=0,x+1=0

x^{2}=\frac{4}{9},x=-1

x=\frac{2}{3},x=-1

Roots = -1,\frac{-2}{3} ,\frac{2}{3}

Hence these lie in between (\frac{-3}{2} ,\frac{3}{2})


8 0
3 years ago
ANSWER BOTH QUESTIONS FOR BRAINLIEST TY :)
Alchen [17]

Answer:

<h2>Angle X; 39</h2><h2>Angle Y; 129</h2>

Step-by-step explanation:

180-90

90

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90-51

39

This is x as well as the angle that is across from it.

x+90=y

39+90=129

y=129.

to find the last angle, we add 90 to 51. This gives us 141.

So, now we add up all of the angles to double check everything. If they all add up to 360 then we are correct.

39+39+51+90+141=

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4 0
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Write the decimal 5.16 in decimal word form
VladimirAG [237]
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4 0
3 years ago
Rhode Island has a population of about 60,000 8th graders in the state. New Jersey has a total of 920,000 8th graders. Calculate
seropon [69]

Answer:

8.6 × 10^5

Step-by-step explanation:

New Jersey 8th graders = 920,000

Rhode island 8th graders = 60,000

Difference in Rhode island 8th graders and New Jersey 8th graders population

= 920,000 - 60,000

= 860,000

Answer in scientific notation

860,000

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8 0
3 years ago
What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2​
tangare [24]

The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2

Expanding the expression, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)

Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

7 0
3 years ago
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