Step-by-step explanation:
1. when x is 0
y will be
4x+2y=10
4(0)+2y=10
0+2y=10
collect like terms
2y=10-0
2y=10
divide both sides by 2
2y/2=10/2
y=5
so when x =0 y will equal to 5
2. when x is 1
y will be
4x+2y=10
4(1)+2y=10
4+2y=10
collect like terms
2y=10-4
2y=6
divide both sides by two
2y/2=6/2
y=3
so when x is 1, y is 3
3. when x is 2
4x+2y=10
4(2)+2y=10
8+2y=10
(CLT) 2y=10-8
2y =2
y= 1
Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
Answer:
Step-by-step explanation:
Let X be the value of 3.2484848.... infinite times
Multiply by 100
Subtract to get
Thus the number 3.248 repeating decimal with 48 repeating in fraction form is
