To best emphasize the number of defects. Manager should use graph 3 (refer the image shown):
If we talk about graph 1, it can also be used but usually we put the time line on the horizontal axis, for the convenience and the quantity to be measured on the y-axis. In the graph 1, the time is placed on the vertical axis (x-axis) so it would not be a good pick for the manager.
Same is the case with graph 2 again we have time on the vertical axis. So it is not a good idea to with graph 2.
Graph 3 could be the best to emphasize the number of defects because first of all time is placed on the horizontal axis and the quantity to be shown is on the vertical axis. Secondly, the range of the vertical axis is less so it is easy to observe the data set on the graph quite distinctively. Therefore, graph 3 is the best pick.
Graph 4 is placed correctly in terms of vertical and horizontal axes but the range of vertical axis is quite high due to which the dispersion or the display of the data is quite compressed and it gets hard to visualize.
Answer: 3/2
Step-by-step explanation:
Slope is the coefficient in front of x, slope tells you how you move when plotting on a graph.
Answer:
-66
Step-by-step explanation:
There will be $66 left after the $12 spent on lunch. 66 + -66 = 0
<u>Answer:</u>
The coordinates of endpoint V is (7,-27)
<u>Solution:</u>
Given that the midpoint of line segment UV is (5,-11) And U is (3,5).
To find the coordinates of V.
The formula for mid-point of a line segment is as follows,
Midpoint of UV is
, 
As per the formula,
=5,
=-11
Here 
Substituting the value of
we get,
=5



Substituting the value of
we get,
=-11



So, the coordinates of V is (7,-27)