Answer:
The last answer choice: Phillip will lose (1/2) of his points in his next crash.
Step-by-step explanation:
For every crash, Phillips points will continue to reduce by (1/2) the amount that he currently has. That means after 1 crash, he will 5,000 points left. After 2 crashes, he will have 2,500 points left. After 3 crashes, he will have 1250 points left. After 4 crashes, he will have 625 points left, and so on like that.
Remark
Without being given choices, we can get answers but they may not be listed among your. The important think is to be working in the same units
Convert miles/hour to m/sec
Now just multiply all the numerators together and divide by all the denominators.
<em><u>Numerators:</u></em> 2.5 * 1.6 * 1000 = 4000
<em><u>Denominators:</u></em> 3600
numerator/denominator = 4000/3600 m/s = 1.111 m/s
Conclusion
Talia is a much faster swimmer than Alina because 1.8 is greater than 1.11. Both numbers are in m/s.
2.5 miles / hour = 1.
15. true 16. false in my coculations.
Answer:
Yes
Step-by-step explanation:
I've done this before.
Answer:
f(2n)-f(n)=log2
b.lg(lg2+lgn)-lglgn
c. f(2n)/f(n)=2
d.2nlg2+nlgn
e.f(2n)/(n)=4
f.f(2n)/f(n)=8
g. f(2n)/f(n)=2
Step-by-step explanation:
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]
from a
f(n)=logn
f(2n)=lg(2n)
f(2n)-f(n)=log2n-logn
lo(2*n)=lg2+lgn-lgn
f(2n)-f(n)=lg2+lgn-lgn
f(2n)-f(n)=log2
2.f(n)=lglgn
F(2n)=lglg2n
f(2n)-f(n)=lglg2n-lglgn
lg2n=lg2+lgn
lg(lg2+lgn)-lglgn
3.f(n)=100n
f(2n)=100(2n)
f(2n)/f(n)=200n/100n
f(2n)/f(n)=2
the time will double
4.f(n)=nlgn
f(2n)=2nlg2n
f(2n)-f(n)=2nlg2n-nlgn
f(2n)-f(n)=2n(lg2+lgn)-nlgn
2nLg2+2nlgn-nlgn
2nlg2+nlgn
5.we shall look for the ratio
f(n)=n^2
f(2n)=2n^2
f(2n)/(n)=2n^2/n^2
f(2n)/(n)=4n^2/n^2
f(2n)/(n)=4
the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare
6.n^3
f(n)=n^3
f(2n)=(2n)^3
f(2n)/f(n)=(2n)^3/n^3
f(2n)/f(n)=8
the ratio will be times 8 the initial
7.2n
f(n)=2n
f(2n)=2(2n)
f(2n)/f(n)=2(2n)/2n
f(2n)/f(n)=2
