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Murljashka [212]
3 years ago
5

There is a difference between a research topic and a research question. A research question provides a foundation for creating a

testable hypothesis. For this discussion, start by generating your own research topic and associated research question. For your research question, state the null and alternative hypothesis. Are your hypotheses one-tailed or two-tailed? Are they directional or non-directional? Explain. With inferential statistics, the goal is to reject the null hypothesis. What does this mean? If we reject the null hypothesis, do we conclude that the alternative hypothesis is correct? Why or why not?
Mathematics
1 answer:
True [87]3 years ago
7 0

The research question is important to a researcher as it helps in solving the issue that the researcher wants to solve.

  • The research topic will be "Social media has an effect on the behavior of children".

  • The research question will be "what effect does social media has on the effects of the behavior of children".

  • The null hypothesis will be "there is no statistical significance between social media and children's behavior".

  • The alternative hypothesis will be "there is a statistical significance between social media and children's behavior".

  • The null hypothesis will be rejected when the p-value is equal to the significance level or it's less than it.

Read related link on:

brainly.com/question/16790506

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Answer:

infinitely many

Step-by-step explanation:

12x + 1 = 3(4x + 1) - 2

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12x + 1 = 12x + 3 - 2

Combine like terms

12x+1 = 12x +1

Subtract 12x from each side

1 =1

Since this is always true, we have infinite solutions

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So all the multiples of 3 are...
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3, 9, 15
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3 years ago
The graph of the function g(x) = x2 + 3x - 4 is shifted 5 units to the left. Plot the zeros of the new function on the provided
Colt1911 [192]
<span>g(x) = x^2 + 3x - 4   (please be sure to use " ^ " to denote exponentiation).

This function factors into g(x) = (x+4)(x-1), and so the zeros are -4 and +1.

If we shift this graph 5 units to the left, we get h(x) = (x+5)^2 + 3(x+5) - 4.

The new zeros will be -4-5    and    1-5,    or  -9 and -4.

</span>
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