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Fantom [35]
3 years ago
5

I don't understand them

Mathematics
1 answer:
Lilit [14]3 years ago
6 0

7: Answer: (x,y)=(\frac{5}{4},\frac{3}{2} )

Substitute the value of Y:

-2x-3(10x-11)=-7

Solve for X:

-2x-3(10x-11)=-7

x=\frac{5}{4}

Substitute the value of X:

x=\frac{5}{4}

y=10*\frac{5}{4}-11

Solve for Y:

y=10*\frac{5}{4}-11

y=\frac{3}{2}

Solution:

(x,y)=(\frac{5}{4},\frac{3}{2} )

8: Answer: (x,y)=(3,-2)

Substitute the value of Y:

4x-3*(-2)=18

Solve for X:

4x-3*(-2)=18

x=3

Solution:

(x,y)=(3,-2)

9: Answer (x,y)=(0,-2)

Substitute the value of Y:

-3x+6(-2+5x)=-12

Solve for X:

-3x+6(-2+5x)=-12

x=0

Substitute the value of X:

x=0

y=-2+5*0

Solve for Y:

y=-2+5*0

y=-2

Solution:

(x,y)=(0,-2)

10: Answer (x,y)=(-3,-6)

Substitute the value of Y:

-5x-(6+4x)=21

Solve for X:

-5x-(6+4x)=21

x=-3

Substitute the value of X:

x=-3

y=6+4x(-3)

Solve for Y:

y=6+4x(-3)

y=-6

Solution:

(x,y)=(-3,-6)

Please mark me brainliest if this helped you :)

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A high school spends approximately $9,000 hosting a football games (e.G. The hourly pay for staff, the electricity, water usage,
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Answer:

<u>$4800</u>

Step-by-step explanation:

The expected net income is the probability when rains multiplied by net income (profit) summed with the probability of not raining with that days net income multiplied.

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Profit/Loss = Income - Cost

Income is 5000

Cost = 9000

So,

Loss = 5000 - 9000 = 4000

Or, Net Income (profit) = - 4000

Now, Change of not raining = 100 - 12 = 88% = 88/100 = 0.88

Profit = Income - Cost

Income = 15,000

Cost = 9000

Net Income (profit) = 15000 - 9000 = 6000

So, we can write the expected net income as:

<u>Expected NI </u>= (0.12)(-4000) + (0.88)(6000) = <u>$4800</u>

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3 years ago
Evaluate the expression 3x^2+4x^3 when x=4.
larisa [96]

Step-by-step explanation:

304

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