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Veronika [31]
3 years ago
5

John's mother is three less than four times John's age. Their combined age is 37. What is John's age?

Mathematics
1 answer:
Komok [63]3 years ago
6 0
I think the answer is 8
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Find p(2) for p(x)=x^4-2x^3-6x^2+5
Ede4ka [16]
(2)^4-2(2)^3-6(2)^2+5
16-64-144+5
-187
4 0
3 years ago
For how many three digit numbers (100 to 999) is the sum of the digits even? (For example, 343 has an even sum of digits: 3 + 4
n200080 [17]

Answer:

there are 425 numbers of three digits whose the sum of the digits is even.

Step-by-step explanation:

Option 1:

It is necessary to accomplish one of the next conditions:

(1) all of the digits are even.

(2) exactly 2 of the digits are odd

Then, for the first condition:

4x5x5 = 100 -> this is because the first digit can not be 0.

for the second condition:

(3C1)*5*5*5-1*5*5 =3*125-25=350

where 3C1 is a combination.  The 3C1 determines which of the three digits is even, and it is necessary to subtract the numbers under 100 with the other 2 digits odd.

So, there are 450 numbers of three digits whose the sum of the digits is even.

Option 2:

there are 900 three digit number and 5*5*5 =125 has 3 odd numbers and 5*5*5+4*5*5+4*5*5=325 has 1 odd number, so there are 450 numbers of three digits whose the sum of the digitis is odd, so 900-450 whose the sum of the digits is even.

4 0
3 years ago
How do I solve x≤100
Molodets [167]

Answer:


Step-by-step explanation:

There's really nothing to solve here.  Rather, you should describe what x≤100 represents.

To draw an appropriate graph, draw an x-axis, mark x=100 with a black dot, and then draw an arrow to the left from this dot.  That's it.  "All x less than or equal to 100."

8 0
3 years ago
For the rectangle provided, the length of this rectangle is 5 mm longer than its width. The perimeter of this rectangle is more
olya-2409 [2.1K]
A) length= w+5
width=w
perimeter=42mm
B) 2(w+5)+2w>42
2w+10+2w>42
4w>32
w>8
The width should be greater than 8 and the length should be more than 13.

Hope this helps!
3 0
3 years ago
If a = 5^x, b = 5^y and a^y×b^x = 25 then prove that: xy =1​
avanturin [10]

a =  {5}^{x}  \\ b =  {5}^{y}  \\  {a}^{y}  \times  {b}^{y}  = 25 \\ prove \: ( {5}^{x} )^{y}  \times ( {5}^{y} ) ^{x}  = 25 \\  {5}^{xy}  \times  {5}^{yx}  = {5}^{2} \\  {5 }^{xy + yx}  = 5^{2}  \\ 5^{2xy}  =  {5}^{2} \\ is \:  \: 2xy = 2 \\ xy =  \frac{2}{2}  \\ xy = 1

3 0
3 years ago
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