Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
Answer:
they are parallel to each other
The last answer is correct
x= 45 degrees
y= 10.9sqrt2
Answer:
calculate it. its not cheating, its like flash cards but better, besides its made for that reason.;)
Step-by-step explanation:
7) Rectangular pyramid:
Length = 8m ; width = 4.6m ; Volume = 88m³
Volume of a rectangular pyramid = (Length * Width * Height)/3
88m³ = (8m * 4.6m * height)/3
88m³ * 3 = 36.8m² * height
264m³ = 36.8m² * height
264m³ / 36.8m² = height
7.2 m = height
8) Cone:
r = 5 in ; volume = 487 in³
Volume of a cone = π r² h/3
487 in³ = 3.14 * (5in)² * h/3
487 in³ * 3 = 3.14 * 25in² * h
1,461 in³ = 78.5 in² * h
1,461 in³ / 78.5 in² = height
18.6 in = height
