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Vladimir [108]
4 years ago
8

a new car has a sticker price of 20950 while the invoice price paid was 18750. what is the dealer markup

Mathematics
2 answers:
maksim [4K]4 years ago
8 0

Answer:

1875= $2200

Step-by-step explanation:


Vlada [557]4 years ago
5 0

11.73%

Step-by-step explanation:

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Express the function y(t)= 4 sin 2πt + 15 cos 2πt in terms of (a) a sine term only. (b) Determine the amplitude, the period, the
Bond [772]

Answer:

See the step by step solution

Step-by-step explanation:

Consider a more general case of the form a\sin(x)+b\cos(x). We want to express it as a sine term only by using the following formula \sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)

The trick  consists on find a number \beta \in [0,2\pi] such that \cos(\beta) = a, \sin(\beta)=b . But, note that since \cos^2(\beta)+\sen^2(\beta)=1 it is most likely that a^2+b^2neq 1. Then, we will use the following equations:

\cos(\beta) =\frac{a}{\sqrt[]{a^2+b^2}=A,\sin(\beta) =\frac{b}{\sqrt[]{a^2+b^2}=B

Then, problem turns out to be

a\sin(x)+b\cos(x)= \sqrt[]{a^2+b^2}(A\sin(x)+B\cos(x)) =\sqrt[]{a^2+b^2}(\sin(x)\cos(\beta)+\sin(\beta)\cos(x))=\sqrt[]{a^2+b^2}\sin(x+\beta),

where \beta = \tan^{-1}(\frac{B}{A})= \tan^{-1}(\frac{b}{a}). So, note that the frequency is the same. Then, a) Taking a=4 and b= 15 we have that 4 sin 2πt + 15 cos 2πt= [tex]\sqrt[]{15^2+4^2}\sin(2\pi t + \tan^{-1}\frac{15}{4})

b) The amplitude is \sqrt[]{15^2+4^2} = \sqrt[]{241}. Since 2\pi rad/s = 1 Hz the frequency is 1 Hz. The period is given by \frac{2\pi}{2\pi} = 1.

c) The function's graph is attached

7 0
3 years ago
Read 2 more answers
Please help i dont understand
Kipish [7]

Answer:

44°

Step-by-step explanation:

Arc 8s equal to the central angle

7 0
3 years ago
What is the slope of the line that passes through the points (-8, -6) and (2, -3)​
Brums [2.3K]

Answer:

3/10

Step-by-step explanation:

Slope = y2 - y1/x2 - x1

-3 + 6/2 +8

3/10

7 0
3 years ago
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Greatest common factor of 12, 60, and 68
Katyanochek1 [597]
To calculate the GCF, you need to list all the prime numbers that will go into each number listed

12: 2, 2, 3
60: 2, 2, 3 5
68: 2,2,17

Now you circle the numbers that are the same in each.

GCF: 2, 2

Multiply these numbers to find the GCF: 4
5 0
3 years ago
Solve for x. 5^11x=25^x+9
4vir4ik [10]
   
\displaystyle\\
5^{11x}=25^{x+9}\\\\
5^{11x}=\Big(5^2\Big)^{x+9}\\\\
5^{11x}=5^{2(x+9)}\\\\
11x = 2(x+9)\\\\
11x = 2x+18\\\\
11x - 2x = 18\\\\
9x = 18\\\\
x =  \frac{18}{9} = \boxed{2}



6 0
3 years ago
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