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andriy [413]
3 years ago
13

Please help me with this.

Mathematics
1 answer:
pshichka [43]3 years ago
6 0

Given:

The quadratic equation is:

3x^2-5x-2=0

To find:

Point that is the solution of given equation.

Solution:

We have,

3x^2-5x-2=0

The quadratic function of the above equation is:

y=3x^2-5x-2

Putting x=1, we get

y=3(1)^2-5(1)-2

y=3-5-2

y=-4

The function passes through the point (1,-4). It means (1,-4) is the solution of given equation but (1,5) is not a solution of given equation.

Therefore, the correct option is A.

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3 years ago
Round 176,257 to the nearest hundred thousand
Luden [163]

The nearest hundred thousand would give you zeros after the comma in 176,257

If the number to the right of the comma in this case the "2" is 4 or less than you don't round the 6 up. If the "2" is 5 or greater than you round the 6 up by one number.

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18 PTS! From the equation below, identify the slope and a point on the line. y−3=−2(x+1)
omeli [17]

<u>ANSWER:  </u>

The slope of the given equation is -2 and a point on the given line is (-1, 3)

<u>SOLUTION:</u>

Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)

We need to find the slope of the given equation and a point through which the given line passes.

Given equation is in the form of point slope form  .i.e \mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right) --- eqn 2

where,"m" is the slope of the line

\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) is point on that line.

Now, by comparing (1) and (2)

m = -2

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so, the slope of the given equation is -2  and a point on the given line is (-1, 3)

7 0
3 years ago
What is the equation of the line that passes through (-3,-1) and has a slope of 3/5? Put your answer in slope-intercept form.
Juli2301 [7.4K]

Answer:

y = 3/5x + 4/5 (1st Option)

Step-by-step explanation:

Step 1: Write known variables

m = 3/5

y = 3/5x + b

Step 2: Find <em>b</em>

-1 = 3/5(-3) + b

-1 = -9/5 + b

b = 4/5

Step 3: Rewrite equation

y = 3/5x + 4/5

3 0
3 years ago
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