Answer:
The y-value of P' is -10.
Step-by-step explanation:
It was given that; triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2).
The translation rule is
To find the image of P, which is P', we have to substitute the coordinates of P(-2,6) to obtain;
Hence the y-value of P' is -10.
Number Two or B would be correct
Answer:
The area and circumference is/are both 4π
Step-by-step explanation:
Formula for the circumference: 2πr
Formula for the area: πr²
2×π×2=4π
The circumference is 4π
π×2²= 4π
The area is 4π
Choices A and B have typos in them, so its not clear what you're trying to say for those parts. However, the domain of 
is 
meaning that x can be 0 or larger. In other words, we can't have x be negative. Similarly, y is the same story because has the inverse 
, but only when , so therefore 
as well. In short you can say both x and y are nonnegative.
To summarize so far, the domain is and the range is
Since x = 0 and y = 0 are the smallest x and y values possible, this means (x,y) = (0,0) is the left-most point or where the graph starts. This is the origin. Choice C is a true statement.
Choice D on the other hand is <u>not</u> a true statement. Graph out and you'll see that a straight line does not form, but instead a nonlinear curve that grows forever. That growth gradually diminishes as x gets larger. Algebraically you can pick three points from the function and show that the slopes are different. Say the three points are P, Q and R. If you can show that slope of PQ does not equal slope of QR, then the function is not linear.
