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Bingel [31]
3 years ago
6

3x −3 y −4 ⋅ 3x 3 y 3

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0
The answer to this question is
-
1
2

3

3
+
3

−
3
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The owner of a local golf course wants to determine the average age of the golfers that play on the course in relation to the av
irakobra [83]

Answer:

a. We are 99% confident that the average age of all golfers that play on the golf course is greater than 21.29

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

99% confidence interval for the average age of golfers that play on the area is (35.683, 43.763), which means that we are 99% confident that the mean age of all golfers who play in the area is a value in this interval, and the best conclusion is given by option A, as the lower bound of the interval is greater than 21.

8 0
3 years ago
A card is picked at random from a deck of cards, after putting it back another card is picked at random. ​Are these two events d
kvv77 [185]

Answer: Independent event

Step-by-step explanation:

When two events are independent of each other, this means that the probability that one event will occurs does not in any way affects the probability of the occurrence of the other event.

For example, card is picked at random from a deck of cards, and after putting it back,thne another card is picked at random. ​The probability of picking the cards is not affected by each other since it is put back.

6 0
3 years ago
-3 + 8n = -5<br> what is n?
nirvana33 [79]
Click link above for the answer
7 0
3 years ago
Read 2 more answers
1) How many triangles will be formed by 13 matchsticks?
krek1111 [17]
1) 4 and one extra

2) 21
3 0
3 years ago
I don't understand what the answer is supposed to be, none of my answers match.
jolli1 [7]

The rational expression is the following

\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}

By applying the sandwich rule:

we have

\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}=\frac{(x-1)(2y)}{(6xy)(5)}

which gives

\frac{\frac{x-1}{6xy}}{\frac{5}{2y}}=\frac{(x-1)(2y)}{(6xy)(5)}=\frac{(x-1)(2y)}{(2\cdot3xy)(5)}=\frac{(x-1)(2y)}{(3x\cdot2y)(5)}=\frac{x-1}{3x\cdot5}=\frac{x-1}{15x}

then, the answer is option 2.

7 0
2 years ago
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