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nata0808 [166]
3 years ago
15

C is the circumcenter of APQR. PC=3x+7, RC=5x-15, & QC=51-X x=[?]

Mathematics
1 answer:
amm18123 years ago
8 0

Answer:

x = 11

Step-by-step explanation:

C is the circumcenter of \triangle PQR

\implies PC=QC=RC (Radii of same circle)

\implies RC=QC

\implies 5x-15=51-x

\implies 5x +x=51+15

\implies 6x =66

\implies \: x =  \frac{66}{6}  \\  \\  \implies \:  \huge \:  \red{x = 11}

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The area of a rectangle is given by 3x^3+14x^2-23x+6
dmitriy555 [2]

The length of the rectangle is defined by (x-1)\cdot \left(x-\frac{1}{3} \right).

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7 0
2 years ago
15.2, 3,6,11,18, ...<br> Describe the pattern. Then write the next three numbers
Misha Larkins [42]

Answer:

27, 38, and 51

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3, 6, 11, 18, ...

We increase the first number by 3.  Then 5.  Then 7.

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3 years ago
HELP PRECALC I DO NOT UNDERSTAND AT ALLLLL!!!!!!!!!!!!!!!!!!!!!!
Arlecino [84]

Answer:

  φ ≈ 1.19029 radians   (≈ 68.2°)

Step-by-step explanation:

There are simple formulas for A and φ in this conversion, but it can be instructive to see how they are derived.

We want to compare ...

  y(t) = Asin(ωt +φ)

to

  y(t) = Psin(ωt) +Qcos(ωt)

Using trig identities to expand the first equation, we have ...

  y(t) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)

Matching coefficients with the second equation, we have ...

  P = Acos(φ)

  Q = Asin(φ)

The ratio of these eliminates A and gives a relation for φ:

  Q/P = sin(φ)/cos(φ)

  Q/P = tan(φ)

  φ = arctan(Q/P) . . . . taking quadrant into account

__

We can also use our equations for P and Q to find A:

  P² +Q² = (Acos(φ))² +(Asin(φ))² = A²(cos(φ)² +sin(φ)²) = A²

  A = √(P² +Q²)

_____

Here, we want φ.

  φ = arctan(Q/P) = arctan(5/2)

  φ ≈ 1.19029 . . . radians

8 0
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