X=5y+10 this is the answer
The expected frequency of east campus and passed is C. 42 students
<h3>How to calculate the value?</h3>
The table for expected frequency is ,
East Campus West Campus Total
Passed (84*100)/22=42 (84*100)/200 =42 84
Failed (116*100)/200=58 (116*100)/22=58 116
Total 100 100 200
Passed = 84×100/200
= 42
Therefore, the expected frequency of East Campus and Passed is 42 students.
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Answer:
For a circle of radius R, the circumference is:
C = 2*pi*R
where pi = 3.14
And if we have an arc defined by an angle θ, the length of the arc is:
A = (θ/360°)*2*pi*R
Here we can not see the image, then i assume that B is the angle that defines the arc AC.
Now we know that the circumference is 120 in, then:
2*pi*R = 120in
Then the length of the arc is:
A = (θ/360°)*120 in
Then if the angle is 18°, we have:
A = (18°/360)*120 in = 6in
2.4x10 to the power of -10
Answer: The answer is B 0.075 cm
Step-by-step explanation:
Since the drawings is a scale of the original you must use a proportion to solve the desired side. 0.045/.9=w/1.5;w=0.075.
