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attashe74 [19]
4 years ago
13

Please help !! How do you convert potential energy to kinetic energy?

Mathematics
1 answer:
VashaNatasha [74]4 years ago
8 0
When you move somewhere
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Math problem I need help​
Gemiola [76]

Answer:

Associative property

Step-by-step explanation:

<u>The given property is:</u>

A + (B +  C) = (A + B) + C

which is called "associative property of addition".

Hence, this property is used in the given expression which is "rearranging the parenthesis does not affect the result."

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
2 years ago
Help me please need it for now
svetlana [45]

Answer:

A- 200+25x

B- 200+25×4=300

Continued for question B: The input of 4 into "x" indicates how many cans of paint you have bought

Step-by-step explanation:

7 0
3 years ago
6x^2=726<br><img src="https://tex.z-dn.net/?f=6x%5E2%20%3D%20726" id="TexFormula1" title="6x^2 = 726" alt="6x^2 = 726" align="ab
Greeley [361]

Answer:

x=11

Step-by-step explanation:

<u>Step 1:  Divide both sides by 6</u>

6x^2 / 6 = 726 / 6

x^2 = 121

<u>Step 2:  Square root both sides</u>

<u />\sqrt{x^2} = \sqrt{121}

x = 11

Answer:  x=11

6 0
3 years ago
Read 2 more answers
A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32 centimeters, and the le
andreyandreev [35.5K]

Answer:

Step-by-step explanation:

First off, since we're talking about finding the correct hypotenuse for the triangle, we know to use the Pythagorean Theorem:
a^2+b^2=c^2

Since we know from the question, 32 and 22 are not the hypotenuse we know that those two values would be a and b. Now, all we do is stick these both into the equation and solve!
32^2+22^2=c^2

1024+484=c^2

1508=c^2

\sqrt{1508}=c

c=38.83cm

5 0
2 years ago
Need help <br> Correct answers only.
disa [49]

The diameter of the circle is the same as the side length of the bounding square. The radius of the circle is 8 in, so the side length of the square is 16 in.

Then the area between the square and circle is obtained by subtracting the area of the circle from the area of the square:

A_{\rm circle}=\pi(8\,\mathrm{in})^2=64\pi\,\mathrm{in}^2

A_{\rm square}=(16\,\mathrm {in})^2=256\,\mathrm{in}^2

and the area you want is

256-64\pi\,\mathrm{in}^2\approx54.9\,\mathrm{in}^2

6 0
4 years ago
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